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Luba_88 [7]
3 years ago
9

The Math Honor Society has 100 members. There are 60 juniors and 40 seniors. The bylaws state that the president has to be a sen

ior and the vice president has to be a junior. The secretary and treasurer can come from any class. How many ways can the president, vice president, secretary, and treasurer be elected assuming all 100 members want the jobs?
Mathematics
2 answers:
dezoksy [38]3 years ago
6 0

Answer:

Took the test answer is 22,814,400

Step-by-step explanation:

melamori03 [73]3 years ago
3 0
40 x 60 x 98 x 97 
There are 40 seniors to be president, 60 juniors to be juniors, 98 people are left since 2 were elected for president and vice president. After the Secretary has been elected, there are 97 people left. SImply multiply the numbers. There are 22,814,400 ways. 
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Answer:

The sum of coefficients = 9

Step-by-step explanation:

The given expression is,

3x⁴ + 5x² + x

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<u>To find the coefficients of each terms </u>

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3x⁴            3

5x²            5

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<u>To find the sum of coefficients </u>

sum = 3 + 5 + 1 = 9

Therefore the sum of coefficients = 9

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