3. Where does solar energy come from? Enter your answer

Based only on the information given in the diagram, it is guaranteed that

makkiz [27]

Answer: True

Step-by-step explanation:

There are two pairs of congruent angles, meaning the triangles are similar by AA.

4 0

3 years ago

A semicircle is cut out of a rectangular paperboard 27in long and 20in wide, as shown below. What is the perimeter of the paperb

guapka [62]

A semicircle is cut out of a rectangular paperboard 27 long and 20in wide, as shown below. What is the perimeter of the paperboard that remains after the semicircle is removed

7 0

4 years ago

The Point-Slope Equation: Pt 2

denis-greek [22]

Answer:

y = -1/3x - 5/3

Step-by-step explanation:

The slope of a line is the ratio of vertical distance to horizontal distance between the points. Since the line has to cross through the point (-5,0), count out the slope -1/3 by moving down 1 unit and to the right 3 units. This places the line between -1 and -2 on the y-axis. Looking at the options listed for b in y = mx + b. b = -5/3 is the best option and is between -1 and -2.

7 0

3 years ago

A standard deck of cards has 52 cards divided into 4 suits, each of which has 13 cards. Two of the suits ($\heartsuit$ and $\dia

Gnoma [55]

Answer:

The number of ways to select 2 cards from 52 cards without replacement is 1326.

The number of ways to select 2 cards from 52 cards in case the order is important is 2652.

Step-by-step explanation:

Combinations is a mathematical procedure to compute the number of ways in which k items can be selected from n different items without replacement and irrespective of the order.

${n\choose k}=\frac{n!}{k!(n-k)!}$

Permutation is a mathematical procedure to determine the number of arrangements of k items from n different items respective of the order of arrangement.

$^{n}P_{k}=\frac{n!}{(n-k)!}$

In this case we need to select two different cards from a pack of 52 cards.

Two cards are selected without replacement:

Compute the number of ways to select 2 cards from 52 cards without replacement as follows:

${n\choose k}=\frac{n!}{k!(n-k)!}$

${52\choose 2}=\frac{52!}{2!(52-2)!}$

$=\frac{52\times 51\times 50!}{2!\times50!}\\=1326$

Thus, the number of ways to select 2 cards from 52 cards without replacement is 1326.

Two cards are selected and the order matters.

Compute the number of ways to select 2 cards from 52 cards in case the order is important as follows:

$^{n}P_{k}=\frac{n!}{(n-k)!}$

$^{52}P_{2}=\frac{52!}{(52-2)!}$

$=\frac{52\times 51\times 52!}{50!}$

$=52\times 51\\=2652$

Thus, the number of ways to select 2 cards from 52 cards in case the order is important is 2652.

6 0

3 years ago

When a particular type of thumbtack is dropped, it will land point up (A flat-top thumbtack resting on its flat top) or point

erma4kov [3.2K]

Answer:

0.48

0.52

No

Yes

Step-by-step explanation:

Result of experiment :

Point up = 48

Point down = 52

Total number of trials = 100

Recall :

Experimental probability = number of outcomes / number of trials

1.)

P(Landing point up) = 48 / 100 = 0.48

2.)

P(Landing point down) = 52 / 100 = 0.52

3.)

The same result will not occur has the outcomes of trials aren't fixed.

4.) Yes, nearly the same result could occur on the second trial, as the number of possible outcubes are just 2 and the number if trials is high.

8 0

3 years ago