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The quadratic function, y = x2, has an x-intercept at the origin = TRUE</span>
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The quadratic function, y = x2 + 3, has an x-intercept at the origin = FALSE</span>
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From x = -2 to x = 0, the average rate of change for both functions is positive = FALSEWhen viewing a graph, you start from the left and go to right and from left to right from -2 to 0 the graph is declining.
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From x = -2 to x = 0, the average rate of change for both functions is negative = TRUEBoth are declining if you read the graph from left to right.
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For the quadratic function, y = x2, the coordinate (2, 3) is a solution to the equation of the function. = FALSE</span><span>
y = x^2
If we insert 2 into y = x^2 we get y = 4 but our point (2,3) has y = 3
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For the quadratic function, y = x2 + 3, the coordinate (2, 7) is a solution to the equation of the function. = TRUE
If we insert 2 for x, we see that y = x^2 + 3 = y = 2^2 + 3 = y = 7 and our y value in the point (2,7) is 7.
Answer:
5
Step-by-step explanation:
The value of "b" is the y-intercept. The point is (3,5). 5 is the y intercept so bb is equal to 5.
Step-by-step explanation:
let (5,-5) =(x1,y1)
from eqn y=3/2x+3
slope (m)=3/2
now,
eqn in slope intercept form is;
(y-y1)=m (x-x1)
- (y-5)=3/2 (x+5)
- 2 (y-5)=3 (x+5)
- 2y-10=3x+15
- 3x-2y+25=0 is required eqn
Yes,the answer is 0. hope it helps