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disa [49]
3 years ago
9

The pool is located at (0,0) to get to your house from the pool you walk three blocks west and one block north what ordered pair

corresponds to the location of your house what quadrant is your house located in

Mathematics
1 answer:
ira [324]3 years ago
8 0

Answer:

(-3, 1) quadrant II (2)

Step-by-step explanation:

An image of the coordinate plane is show.  The quadrants start at the top right and move around in the counter-clockwise direction.  The x-axis is horizontal (side to side) and y-axis is vertical (up and down).  Starting at the origin of the coordinate plane (0, 0) and going three blocks west (left) would put you at -3 on the x-axis.  If you then proceed to go north (up) +1, you would now be at point (-3, 1) which is a (-x, +y)  or in quadrant II.  

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each value to the correct expressio
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Give three equivalent rates that describe the top speed of a tuna.
WINSTONCH [101]

Answers:

35 much faster - Shark animal

Step-by-step explanation:

so

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3 0
3 years ago
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La barbería El Caleño, tiene en promedio 120 clientes a la semana a
Luba_88 [7]

Queremos maximizar el precio de tal forma que los ingresos no disminuyan.

Ese maximo precio es: $14,040.6

Sabemos que actualmente el precio es:

p = $6,000

El número de clientes es:

C = 120

Actualmente los ingresos son el producto de esos dos números, es decir:

ingresos = $6,000*120 = $720,000

Ahora sabemos que por cada incremento de $700 en el precio, el número de clientes decrece en 10.

Entonces podemos escribir el número de clientes como una ecuación lineal.

C(p) = a*p + b

tal que tenemos dos puntos en esa linea:

($6,000, 120)

($6,700, 110)

La pendiente es:

a = \frac{110 - 120}{\$6,700 - \$6,000} = \frac{-10}{\$ 700}

Entonces tenemos:

C(p) = (-10/$700)*p + b

Sabemos que:

C($6,000) = 120 = (-10/$700)*$6,000 + b

                     120 = -85.71 + b

                     120 + 85.71 = b =

Entonces la ecuación lineal es:

C(p) = (-10/$700)*p + 205.71

Los ingresos serán dados por:

ingresos = C(p)*p = (-10/$700)*p^2 + 205.71*p

Y queremos maximizar p de tal forma que esto sea igual a lo que obtuvimos antes:

(-10/$700)*p^2 + 205.71*p = $720,000

Entonces debemos resolver la ecuación cuadratica:

(-10/$700)*p^2 + 205.71*p - $720,000 = 0.

Las soluciones son dadas por la formula de Bhaskara.

p = \frac{-205.71 \pm \sqrt{(205.71)^2 - 4*(-10/\$ 700)*\$ 720,000} }{2*(-10/\$ 700)} \\\\p = \frac{-205.71 \pm 195.45}{(-20/\$ 700)}

La solución de maximo valor es:

p = (-205.71 - 195.45)/(-20/$700) = $14,040.6

Sí quieres aprender más, puedes leer.

brainly.com/question/8926135

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Answer:

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Step-by-step explanation:

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2 years ago
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