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2 years ago

Dhruv is at a car dealership. He is going to randomly select a vehicle to test drive. There are

Mathematics

1 answer:

andrew-mc [135]2 years ago

8 0

Answer:

P(compact cars) = 4/25

Step-by-step explanation:

We know that there are 13 trucks, 8 vans, and 4 compact cars.

Let P denotes the probability of an event

Now we are asked to find the probability of compact cars

Number of favorable events = number of compact cars = 4

total number of outcomes = 13+8+4 = 25

hence, P(compact cars) = number of favorable events/total outcomes

=4/25

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How to solve x(x-3)=0

damaskus [11]

Step-by-step explanation:

x(x-3)=0

x=0 or (x-3) =0

x= 0 or x =3

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3 years ago

Which list correctly orders A, B, and C from least to greatest when A= |7|, B = _6, and C = |-5|?

zheka24 [161]

Answer:

D. B,C,A

Step-by-step explanation:

A= |7|=7

B= -6

C= |-5|=5

so this means that B<C<A = -6<5<7

so; B,C,A = -6,7,5

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3 years ago

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Artyom0805 [142]

Answer:

8 pt

Step-by-step explanation:

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3 years ago

If P->q is true and q->r is true them the conclusión of p->r is also true this is called?

tino4ka555 [31]

Answer:

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3 years ago

Of the smoothies sold yesterday at Marlins smoothie shop, 5/6 were banana and another 1/12 were strawberry . What fraction of th

professor190 [17]

Answer:

The fraction of smoothies sold were either banana or strawberry is $\frac{11}{12}.$

Step-by-step explanation:

Given:

Of the smoothies sold yesterday at Marlins smoothie shop, 5/6 were banana and another 1/12 were strawberry.

Now, to find the fraction of the smoothies sold were either banana or strawberry.

Fraction of smoothie were of banana = $\frac{5}{6} .$

Fraction of smoothie were of strawberry = $\frac{1}{12} .$

Now, to get the fraction smoothies sold were either banana or strawberry by adding both the fractions of banana and strawberry:

$\frac{5}{6} +\frac{1}{12} \\\\=\frac{10+1}{12} \\\\=\frac{11}{12}$

Therefore, the fraction of smoothies sold were either banana or strawberry is $\frac{11}{12}.$

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3 years ago