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shutvik [7]
3 years ago
9

Logan has a change jar that contains only pennies and nickels. he has 64 coins which add up to a total of $1.52. how many of eac

h type of coin does he have?
Mathematics
2 answers:
Svetach [21]3 years ago
7 0
42 pennies 22 nickels 22x.05=1.10 1.10+.42=1.52
jekas [21]3 years ago
4 0
12 nickels and 4 pennys
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Dima020 [189]

Answer:

Can you explain the question lol in so confused

Step-by-step explanation:

8 0
2 years ago
2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi
Oksana_A [137]

Answer:

(a) E(X) = 950

(b) $ COV = 0.007255$

(c) P(X > 980) = 0.00001\\\\

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$ COV = \frac{\sigma}{E(X)} $

Where the standard deviation is given by

\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892

So the coefficient of variance is

$ COV = \frac{6.892}{950} $

$ COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

P(X > 980)  = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980)  = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980)  = 1 - P(Z < 4.28)\\\\

The z-score corresponding to 4.28 is 0.99999

P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\

So it means that it is very unlikely that there will be more than 980 non-defective units.

8 0
3 years ago
Find the area for all of them. Pleaseee help me I don’t understand.
tester [92]

Answer:

Step-by-step explanation:

top = 120sq m

middle = 17sq cm

bottom = 102 sq feet

4 0
2 years ago
Mrs. Summers polled the students in her 7th and 8th grade classes to determine the number of pets each student has at home. The
Aleonysh [2.5K]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the value of the fourth term in a geometric sequence for which a1= 30 and r = 1/2
Viktor [21]

Answer:

a_{4} = 3.75

Step-by-step explanation:

The n th term of a geometric sequence is

a_{n} = a₁(r)^{n-1}

where a₁ is the first term and r the common ratio

Here a₁ = 30 and r = \frac{1}{2}, thus

a_{4} = 30(\frac{1}{2}) ^{3} = 30 × \frac{1}{8} = \frac{30}{8} = \frac{15}{4} = 3.75

4 0
3 years ago
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