Answer: A. Multicast
Explanation:
Here we are given a situation where it is necessary for the device to stream media to all the PCs connected across the LAN. But as the they are unable to stream the media then it is a problem in the multicast TCP/Ip technology.
Multicasting enables to transfer information or messages from one to many or many to many. Here as a single device is responsible for streaming the content to other PCs across the LAN, therefore it is necessary that multicast has been properly implemented.
Option B is incorrect as it is not a scenario of broadcast as in broadcasting all the receivers must get the streaming however here if a PC does not want to receive the media stream it cannot receive for which multicasting is required.
Option C is incorrect as here we are not talking of one to one communication.
Option D is incorrect as here we cannot have more than one route to send the media content except the LAN.
Answer:
Check the explanation
Explanation:
#include <iostream>
using namespace std;
void hex2dec(string hex_num){
int n = 0;
//Loop through all characters in string
for(int i=0;i<hex_num.size();i++){
//take ith character
char c = hex_num[i];
//Check if c is digit
if(c>='0' && c<='9'){
n = 16*n + (c-48);
}
//Convert c to decimal
else{
n = 16*n + (c-55);
}
}
cout<<hex_num<<" : "<<n<<endl;
}
int main()
{
hex2dec("EF10");
hex2dec("AA");
return 0;
}
The Output can be seen below :
Answer:
the smart phone
Explanation:
It is the most widley used and accepted
C. ">" denotes the end of an element. For instance <b>Hello!</b> or <hr />
Answer:
def analyze_text(sentence):
count = 0
e_count = 0
for s in sentence:
s = s.lower()
if s.isalpha():
count += 1
if s == "e":
e_count += 1
return "The text contains " + str(count) + " alphabetic characters, of which " + str(e_count) + " (" + str(e_count*100/count) + "%) are ‘e’."
Explanation:
Create a function called analyze_text takes a string, sentence
Initialize the count and e_count variables as 0
Create a for loop that iterates through the sentence
Inside the loop, convert all letters to lowercase using lower() function. Check each character. If a character is a letter, increment the count by 1. If a character is "e", increment the e_count by 1.
Return the count and e_count in required format
