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ladessa [460]
4 years ago
8

(QUICK RESPONSE!!!) Which graph shows the solution set for 2 x + 3 greater-than negative 9?

Mathematics
1 answer:
iris [78.8K]4 years ago
6 0

Answer:

It's the last answer choice

Step-by-step explanation:

2x+3> -9

2x+3-3> -9-3

2x> -12

2x/2> -12/2

x> -6

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David y Almudena tienen entre los dos 225 euros. Calcula cuánto dinero tiene cada uno si Almudena posee 75 euros más que David.
Misha Larkins [42]

David and Almudena have between the two 225 euros. Calculate how much money each has if Almudena has 75 euros more than David.

For this case we propose a system of equations:

x: Let the variable that represents Almudena's amount of money

y: Let the variable that represents David's amount of money

According to the statement we have:

x + y = 225\\y + 75 = x

Substituting the second equation into the first:

y + 75 + y = 225\\2y + 75 = 225\\2y = 225-75\\2y = 150\\y = \frac {150} {2}\\y = 75

We find the value of the variable x:

x = 75 + 75 = 150

Almudena has 150 euros

David has 75 euros

Answer:

Almudena has 150 euros

David has 75 euros

3 0
4 years ago
In 6 minutes, Latoya can type 18 words. What is her rate in words per minute?
Lemur [1.5K]
The rate in words per minute would be 3 because 18/6 is equal to 3
7 0
3 years ago
How does a digit in the ten thousand place compare to a digit in the thousands place
dezoksy [38]
It is ten times bigger than the other
4 0
3 years ago
Let an be the sum of the first n positive odd integers.
sesenic [268]

Answer:

A) The first 4 terms of the sequences are: a_{1} =16, a_{2} =24, a_{3} =32 and a_{4} =40.

B) An explicit formula for this sequence can be written as: a_{n} =8*(n+1)

C) A recursive formula for this sequence can be written as:

\left \{ {{a_{1} =16} \atop {a_{n} =a_{n-1}+8}} \right.

Step-by-step explanation:

A) You can find the firs terms of this sequence simply selecting an odd integer and summing the consecutive 3 ones:

a_{n} = Odd_{n}+Odd_{n+1}+Odd_{n+2}+Odd_{n+3} (a.1)

a_{1}=1+3+5+7=16

a_{2}=3+5+7+9=24

a_{3}=5+7+9+11=32

a_{4}=7+9+11+13=40

B) Observe the sequence of odd numbers 1, 3, 5, 7, 9, 11, 13(...).

You can express this sequence as:

Odd_{n}=(2*n-1) (b.1)

If you merge the expression b.1 in a.1, you obtain the explicit formula of the sequence:

a_{n} = Odd_{n}+Odd_{n+1}+Odd_{n+2}+Odd_{n+3} (a.1)

a_{n} = (2*n-1)+((2*(n+1)-1))+((2*(n+2)-1))+((2*(n+3)-1)) (b.2)

a_{n} = 8*n+8 (b.3)

a_{n} =8*(n+1) (b.s)

C) The recursive formula has to be written considering an initial term and an N term linked with the previous term. You can see an addition of 8 between a term and the next one. So you can express each term as an addition of 8 with the previous one. Therefore, if the first term is 16:

\left \{ {{a_{1} =16} \atop {a_{n} =a_{n-1}+8}} \right. (c.s)

5 0
3 years ago
Factorizie completely 2ap+aq-bq-2bp​
anyanavicka [17]

Answer:

2ap + aq - bq -2bp = (a - b)(2p + q)

Step-by-step explanation:

(2ap + aq) - (bq -2bp)

a(2p +q) -b(q + 2p)    [ taking a common from the first, and b from the second]

(2p + q) [a - b]           [takin (2p + q)]

(2p + q)(a - b)

4 0
3 years ago
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