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lesya [120]
3 years ago
10

Nikhil gets paid a 5 percent commission on every pair of shoes that he sells. He earned $1.00 on the last pair of shoes that he

sold. The expression that can be used to represent x, the price of the shoes, is 0.05 x = 1 What was the price of the shoes?
$5.00
$10.00
$20.00
$25.00
Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
6 0

Answer:

the correct answer is C $20

Step-by-step explanation:

Pls Mark me brainiest ;)))

Pepsi [2]3 years ago
3 0

Answer: The answer is C. $20.00

Step-by-step explanation:

You might be interested in
-2x + y = 4<br> y = x + 2<br><br><br> Third question^ solve the system of equations
Leya [2.2K]

Answer:

x=-2 y=0

Step-by-step explanation:

put the second equation in to the first one

-2x+x+2=4

-x=2

x=-2

y=-2+2=0

x=-2 y=0

6 0
2 years ago
Geometry question. please help ​
Vinvika [58]

Answer:

The length of PQ is <u>18</u> feet.

The length of PR is <u>18</u> feet.

The length of QR is <u>24</u> feet.

Step-by-step explanation:

A way to set an equation up for this problem is:

\frac{4}{3}x+x+x=60

where x is the three lengths of the isosceles triangle, but the base QR is 4/3 the length of the other two congruent sides, length PQ and PR. The 60 represents the total length of the perimeter.

Then, solve for x from the equation, and you’ll get x=18. But your not done yet. Since the variable x in the equation stands for the sides of the isosceles triangle, so plug 18 into the equation and it should look like this:

\frac{4}{3}(18)+18+18=60

Don’t solve the whole equation, just solve the \frac{4}{3}(18) part of the equation, which is equal to 24. So the final equation is this:

24+18+18=60

Conclusion: 24 is the length of QR, and 18 is the length of PQ and PR. And they all equal 60, which is the perimeter. This is very true because the length of PQ and PR are the same (length 18), since it’s an isosceles triangle, and the length of QR is 4/3 the length of PQ and PR (4/3 of 18= 24).

Sorry for the long explanation.

But hope this helps and answers your question :)

8 0
2 years ago
3) If the population of the United States increased to 420 million and the number of
shutvik [7]

Answer:

About 965517 Americans.

7 0
2 years ago
Read 2 more answers
Mei has 8 jars of soup. Each jar contains 300 milliliters of soup. What is the smallest pot Mei can use to heat all the soup.[PL
Kobotan [32]

Answer: A pot of 2400ml

Step-by-step explanation: Ok, mei has 8 jars, and each jar has 300ml of soup, so the total amount of soup is 8 times 300ml

N = 8*300ml = 2400ml

So the smallest pot that mei can use to heat the soup is a pot that has exactly that volume. 2400ml, (discarding the fact that the volume of the soup will change as it is heated up)

7 0
3 years ago
"find the reduction formula for the integral" sin^n(18x)
dexar [7]
Let

I(n,a)=\displaystyle\int\sin^nax\,\mathrm dx
For demonstration on how to tackle this sort of problem, I'll only work through the case where n is odd. We can write

\displaystyle\int\sin^nax\,\mathrm dx=\int\sin^{n-2}ax\sin^2ax\,\mathrm dx=\int\sin^{n-2}ax(1-\cos^2ax)\,\mathrm dx
\implies I(n,a)=I(n-2,a)-\displaystyle\int\sin^{n-2}ax\cos^2ax\,\mathrm dx

For the remaining integral, we can integrate by parts, taking

u=\sin^{n-3}ax\implies\mathrm du=a(n-3)\sin^{n-4}ax\cos ax\,\mathrm dx\mathrm dv=\sin ax\cos^2ax\,\mathrm dx\implies v=-\dfrac1{3a}\cos^3ax

\implies\displaystyle\int\sin^{n-2}ax\cos^2ax\,\mathrm dx=-\dfrac1{3a}\sin^{n-3}ax\cos^3ax+\dfrac{a(n-3)}{3a}\int\sin^{n-4}ax\cos^4ax\,\mathrm dx

For this next integral, we rewrite the integrand

\sin^{n-4}ax\cos^4ax=\sin^{n-4}ax(1-\sin^2ax)^2=\sin^{n-4}ax-2\sin^{n-2}ax+\sin^nax
\implies\displaystyle\int\sin^{n-4}ax\cos^4ax\,\mathrm dx=I(n-4,a)-2I(n-2,a)+I(n,a)

So putting everything together, we found

I(n,a)=I(n-2,a)-\displaystyle\int\sin^{n-2}ax\cos^2ax\,\mathrm dx
I(n,a)=I(n-2,a)-\left(-\dfrac1{3a}\sin^{n-3}ax\cos^3ax+\dfrac{n-3}3\displaystyle\int\sin^{n-4}ax\cos^4ax\,\mathrm dx\right)
I(n,a)=I(n-2,a)-\dfrac{n-3}3\bigg(I(n-4,a)-2I(n-2,a)+I(n,a)\bigg)+\dfrac1{3a}\sin^{n-3}ax\cos^3ax
\dfrac n3I(n,a)=\dfrac{2n-3}3I(n-2,a)-\dfrac{n-3}3I(n-4,a)+\dfrac1{3a}\sin^{n-3}ax\cos^3ax

\implies I(n,a)=\dfrac{2n-3}nI(n-2,a)-\dfrac{n-3}nI(n-4,a)+\dfrac1{na}\sin^{n-3}ax\cos^3ax
7 0
2 years ago
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