<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>
Answer: A IS CORRECT
Step-by-step explanation:
Answer:
y = 1/3x + 4 1/3
Step-by-step explanation:
2x - 6y = 12
First find the slope
Solve for y
Subtract 2x
2x - 6y -2x= 12-2x
-6y = -2x+12
Divide by -6
-6y/-6 =-2x/-6 +12/-6
y = 1/3 x -2
The slope is 1/3
Parallel lines have the same slope
Using the slope intercept form y = mx+b where m is the slope and b is the y intercept
y = 1/3x +b
And substituting in the point
4 = 1/3 (-1) +b
4 = -1/3 +b
Add 1/3 to each side
4 + 1/3 = b
y = 1/3x + 4 1/3
The product of A and B matrix will be option D; BA =
.
<h3>What is the multiplication of matrix?</h3>
If
and ![B = \left[\begin{array}{ccc}2&3&-5\\5&-4&2\\-1&-1&3\end{array}\right]](https://tex.z-dn.net/?f=B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%26-5%5C%5C5%26-4%262%5C%5C-1%26-1%263%5Cend%7Barray%7D%5Cright%5D)
then,
BA = ![\left[\begin{array}{ccc}2&3&-5\\5&-4&2\\-1&-1&3\end{array}\right] \left[\begin{array}{ccc}-2&-4&2\\5&1&5\\-1&-3&-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%26-5%5C%5C5%26-4%262%5C%5C-1%26-1%263%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%26-4%262%5C%5C5%261%265%5C%5C-1%26-3%26-4%5Cend%7Barray%7D%5Cright%5D)
BA = ![\left[\begin{array}{ccc}16&10&39\\-32&-30&-18\\-6&-6&-19\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%2610%2639%5C%5C-32%26-30%26-18%5C%5C-6%26-6%26-19%5Cend%7Barray%7D%5Cright%5D)
Hence, the product of A and B matrix will be option D; BA =
.
Learn more about matrix here;
brainly.com/question/9967572
#SPJ1
<span>the answer is x² + (y + 3)² = 4 C. i just did the problem</span>