<u>Answer:</u>
<u>For A:</u> The mass of iron (III) sulfate is 600. g
<u>For B:</u> The moles of ammonium carbonate is 0.07216 moles
<u>For C:</u> The mass of given number of molecules of aspirin is 0.359 grams.
<u>For D:</u> The molar mass of diazepam is 284.7 g/mol
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
We are given:
Number of moles of iron (III) sulfate = 1.50 mol
Molar mass of iron (III) sulfate = 399.9 g/mol
Putting values in equation 1, we get:
![1.50mol=\frac{\text{Mass of iron (III) sulfate}}{399.9g/mol}\\\\\text{Mass of iron (III) sulfate}=(1.50mol\times 399.9g/mol)=600.g](https://tex.z-dn.net/?f=1.50mol%3D%5Cfrac%7B%5Ctext%7BMass%20of%20iron%20%28III%29%20sulfate%7D%7D%7B399.9g%2Fmol%7D%5C%5C%5C%5C%5Ctext%7BMass%20of%20iron%20%28III%29%20sulfate%7D%3D%281.50mol%5Ctimes%20399.9g%2Fmol%29%3D600.g)
Hence, the mass of iron (III) sulfate is 600. g
We are given:
Mass of ammonium carbonate = 6.935 g
Molar mass of ammonium carbonate = 96.1 g/mol
Putting values in equation 1, we get:
![\text{Moles of ammonium carbonate}=\frac{6.935g}{96.1g/mol}=0.07216mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20ammonium%20carbonate%7D%3D%5Cfrac%7B6.935g%7D%7B96.1g%2Fmol%7D%3D0.07216mol)
Hence, the moles of ammonium carbonate is 0.07216 moles
We are given:
Number of aspirin molecules = ![1.20\times 10^{21}](https://tex.z-dn.net/?f=1.20%5Ctimes%2010%5E%7B21%7D)
Mass of 1 mole of aspirin = 180.16 g/mol
According to mole concept:
number of molecules occupies 1 mole
So,
number of molecules of aspirin has a mass of 180.16 grams
Thus,
number of molecules of aspirin will have a mass of ![\frac{180.16g}{6.022\times 10^{23}}\times 1.20\times 10^{21}=0.359g](https://tex.z-dn.net/?f=%5Cfrac%7B180.16g%7D%7B6.022%5Ctimes%2010%5E%7B23%7D%7D%5Ctimes%201.20%5Ctimes%2010%5E%7B21%7D%3D0.359g)
Hence, the mass of given number of molecules of aspirin is 0.359 grams.
We are given:
Moles of diazepam = 0.05570 mol
Given mass of diazepam = 15.86 g
Putting values in equation 1, we get:
![0.05570mol=\frac{15.86g}{\text{Molar mass of diazepam}}\\\\\text{Molar mass of diazepam}=\frac{15.86g}{0.05570mol}=284.7g/mol](https://tex.z-dn.net/?f=0.05570mol%3D%5Cfrac%7B15.86g%7D%7B%5Ctext%7BMolar%20mass%20of%20diazepam%7D%7D%5C%5C%5C%5C%5Ctext%7BMolar%20mass%20of%20diazepam%7D%3D%5Cfrac%7B15.86g%7D%7B0.05570mol%7D%3D284.7g%2Fmol)
Hence, the molar mass of diazepam is 284.7 g/mol