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AfilCa [17]
2 years ago
5

I need help on this question on standard enthalpy of formation

Chemistry
1 answer:
forsale [732]2 years ago
7 0

Answer:

B: Na(s) + Cl2(g) + 3O2(g) = 2NaClO3(s)

Explanation:

We are looking for enthalpy of formation, so we want to see reactance in their natural standard form.

Thus, we want to see the reactance of Na, Cl2 and O2.

The only option that has the correct form of Na, Cl2 and O2 is B.

Na(s) + Cl2(g) + 3O2(g) = 2NaClO3(s)

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Specific heat capacity of any substance comes with the unit : J/(g*degree C)
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O = 16 g

2.02 + 16  =  18.02  g

Now  :-    4.18  J / mol- degree C) *  18.02 /  1 mole H2O
molar heat  =  75.3 J / mol - degree C



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