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AfilCa [17]
3 years ago
5

I need help on this question on standard enthalpy of formation

Chemistry
1 answer:
forsale [732]3 years ago
7 0

Answer:

B: Na(s) + Cl2(g) + 3O2(g) = 2NaClO3(s)

Explanation:

We are looking for enthalpy of formation, so we want to see reactance in their natural standard form.

Thus, we want to see the reactance of Na, Cl2 and O2.

The only option that has the correct form of Na, Cl2 and O2 is B.

Na(s) + Cl2(g) + 3O2(g) = 2NaClO3(s)

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Iron is extracted from iron oxide in the Blast Furnace: Fe 2 O 3 + 3 CO → 2 Fe + 3 CO 2
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b. percent yield = 93%

<h3>Further eplanation </h3>

Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

a.

Reaction

Fe₂O₃+3CO⇒2Fe+3CO₂

MW Fe₂O₃ :  159.69 g/mol

mol Fe₂O₃

\tt \dfrac{100}{159,69}=0.626

mol Fe₂O₃ : mol Fe = 1 : 2

mol Fe :

\tt \dfrac{2}{1}\times 0.626=1.252

mass of Fe(Ar=55.845 g/mol) :

\tt 1.252\times 55.845=69.92~g

b.

actual yield = 65 g

theoretical yield = 69.92 g

percent yield :

\tt =\dfrac{65}{69.92}=0.93=93\%

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3 years ago
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