Slope of the line J
(6-1) / (-3-(-6))
5 / 3
so
m = 5/3
If this line passes through (15,-1)
y = mx + c
-1 = (5/3)*15 + c
-1 = 25 + c
c = -26
equation is
y = (5/3)x - 26
Problem
Write the slope-intercept form of the line described in the following:
Parallel to 4x + 5y=20
and passing through (12,4)
Solution>
For this case we need to have the same slope, and if we write the equation given we see:
5y = 20 -4x
y = 4 -4/5 x
then the slope m = -4/5
and we also know a point given x= 12, y= 4 and we can do the following:
4 = -4/5 (12) +b
4 = -48/5 + b
And if we solve for the intercept we got:
b= 4 +48/5= -28/5
And our equation would be given by:
y = -4/5 x -28/5
Answer:
-2(2x+4)
Step-by-step explanation:
Answer:
6g -3g +6g -3g = 5+6-11-3+5-11
6g=-18
6g= -18 /÷6
g= -3
