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Alja [10]
3 years ago
14

What times what equals 57

Mathematics
2 answers:
Ilya [14]3 years ago
6 0
Well 9x6.4=57.6. Thats the closest to 57
irinina [24]3 years ago
4 0
The answer is 1×57=57 right
You might be interested in
Mhanifa please help i will mark brainliest
ioda

Answer:

<u>Use Pythagorean:</u>

  • a² + b² = c²
<h3>#1</h3>
  • x² = 16² - 8²
  • x² = 192
  • x = √192
  • x = 12.73, not an integer

<u>Not a Pythagorean triple</u>

<h3>#2</h3>
  • x² = 40² + 9²
  • x² = 1681
  • x = √1681
  • x = 41

<u>It is a Pythagorean triple (9, 40, 41)</u>

<h3>#3</h3>
  • x² = 6² + 13²
  • x² = 205
  • x = √205
  • x = 14.32, not an integer

<u>Not a Pythagorean triple</u>

4 0
3 years ago
A store marked up the prices p of its merchandise by 11%. The marked-up prices of the merchandise can be written as 1.11p. Which
Y_Kistochka [10]

Answer:

p + 0.11p

Step-by-step explanation:

The merchandise is marked up 11%. This means you pay 100% of the price plus 11%. We can represent that as (1+r) where r is the percent marked above. For 11%, this expression would be 1+0.11. We multiply that by the price p. p(1+0.11). This simplifies to p+0.11p. We can further simplify it to 1.11p.

P(1+r) = p(1+0.11)= p+0.11p=1.11p


8 0
4 years ago
Prove that sin^3x+sincos^2x=sinx
almond37 [142]

Step-by-step explanation:

factor sin(x) out of the equation

sin(x) * (sin^{2} (x) + cos^{2} (x)) = sin(x)

Use the trigonometric identity sin^{2} (x) + cos^{2}(x) = 1

sin(x) * 1 = sin(x)

sin(x) = sin(x)

6 0
3 years ago
I need help to solve this and also Hearn will the bacteria be over 100,000
lapo4ka [179]

Hello! Let's look at the two parts of this question.

Complete the table:

In this case, you just substitute the value of "hour" into the equation, for the value of t. For example:

P(0) = 120 (2)^{0}

P(0) = 120 (1)

P(0) = 120

Therefore, the number of bacteria for hour 0 is 120.

You can do this for the next ones. Hour 1 = 240, hour 2 = 480, and so on. (In this case, you can keep multiplying by 2)

Estimate when there will be more than 100,000 bacteria:

Set the final value of P(t) = 100,000, then solve.

100,000 = 120 (2)^{t}

833.33 = (2)^{t}

t = log_{2}833.33

t = 9.702744108

So your answer would be around 9.7 years, or, around 10 years.

Hope this helps!

3 0
3 years ago
Yyoooo free moneys but im deleting the question if u dont say the right thing in the answer.
Zielflug [23.3K]

UR MOM

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3 0
3 years ago
Read 2 more answers
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