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Law Incorporation [45]

3 years ago

14

pedro mixed 1 pound 6 ounces of apples 1 pound 4 ounces of oranges and 12 ounces of strawberries to make a fruit salad how much

fruit salad does he have

1 answer:

Goshia [24]3 years ago

8 0

Pedro has 3 pounds and 10 ounces of fruit salad

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1+1 = what is it the number<br>

anzhelika [568]

The answer is 2 if this is right can i please have brainlyest

4 0

3 years ago

Read 2 more answers

Before a basketball game a referee noticed that the ball seemed under inflated. She dropped it from 6 feet and measured the firs

deff fn [24]

Answer: a) H = h( 0.5 )^n

b) H = 1.125inches

Step-by-step explanation:

Let H = height of the ball

n = number of time the ball bounces

h = initial height.

The exponential function to model the height of the ball will be:

H = h( 1 - 0.5)^n

H = h( 0.5 )^n

It's minus because the height of the ball is decreasing.

h = 36 inches

n = 5

H = 36( 1 - 0.5 ) ^5

H = 36( 0.5 )^5

H = 36 × 0.03125

H = 1.125inches

7 0

3 years ago

Fill in the arrows with the correct answer for each problem. Remember, begin at the START button highlighted in yellow.

Aliun [14]

Answer:

first 2.70, 4.00 , 7.20 , 7.65 , 6.00 , 12.60 , 62.50 , 45.00 ,32,00 , 12.60 and 2.00 done

Step-by-step explanation:

all correct

4 0

3 years ago

Read 2 more answers

Prove that 3^17−3^15+3^13 is divisible by 73.<br><br> HELPPPPPP PLEASEEE

Fiesta28 [93]

Answer:

Well 3^17-3^15+3^13 equals 116,385,579

Now divide that by 73

So 116,385,579 ÷ 73

That equals 1,594,323

Hope this helps

4 0

2 years ago

Read 2 more answers

In 1990, California switched from a 6/49 lottery to a 6/53 lottery. Later, the state switched again to a 6/51 lottery. (a) Find

zalisa [80]

Answer:

(a) 9.9321*10^{-11}

(b) 6.0498*10^{-11}

(c) 7.7120^{-11}

(d) 1.6417 times more probable

Step-by-step explanation:

(a) The probability of winning a 6/49 lottery is given by:

$P = \frac{1}{49*48*47*46*45*44} =9.9321*10^{-11}$

(b) The probability of winning a 6/53 lottery is given by:

$P = \frac{1}{53*52*51*50*49*48} =6.0498*10^{-11}$

(c) The probability of winning a 6/51 lottery is given by:

$P = \frac{1}{51*50*49*48*47*46} =7.7120^{-11}$

(d) The ratio between the probabilities of winning the 6/49 lottery and winning the 6/53 lottery is:

$r=\frac{9.9321*10^{-11}}{6.0498^{-11}}\\r=1.6417$

It is 1.6417 times more probable.

8 0

4 years ago