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SashulF [63]
2 years ago
11

How much will joseph have to pay

Mathematics
2 answers:
koban [17]2 years ago
6 0
40% of 740 is 444, and 30% of 444 is 133.2 ,so the answer is $133.2
Rudiy272 years ago
6 0

Answer:

$310.8 or $310

Step-by-step explanation:

Sorry if this is wrong  :(

Bye, have a good Day/Night  :)

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What is the value of m? -3m + 6 = -27 *
NISA [10]

Answer: m = -11

Step-by-step explanation:

-3m + 6 = -27

=> -3m = 33

=> m = -11

3 0
3 years ago
Read 2 more answers
Suppose that you work part-time as a sales representative at a car dealership. You earn a base salary of $125 per week plus a 18
elena-14-01-66 [18.8K]
Define the two friends as person A and person B.

Let x =  the sales in a week.

Person A:
$125 per week plus 18% commission on sales.
Earnings in a week on x sales is
125 + 0.18x

Person B:
$85 per week plus 21% commission on sales.
Earnings in a week on x sales is
85 + 0.21x

For the two earnings to be equal,
85 + 0.21x = 125 + 0.18x
0.03x = 40
x = 40/0.03 = $1333.33

Answer: $1,333.33

3 0
4 years ago
.25x + 2x<br> QUICKKKK I NEED HELPPPP
julsineya [31]

Answer:

2.25x

Step-by-step explanation:

2.00x

0.25x

<u>             </u>

2.25x

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5 0
3 years ago
P
beks73 [17]

Answer:

The required equation is D=0.5(4)

Step-by-step explanation:

Consider the provided information.

Student on the cross-country team runs 30 minutes a day as a part of her training,

30 minutes = 0.5 hours

As we know Speed=\frac{Distance}{Time}

Let the distance she runs in miles, is represented by D, and her running speed, in miles per hour is represented by S.

Therefore, the required equation is: S=\frac{D}{0.5}

Part (A) At a constant speed of 4 miles per hour for the entire 30 minutes​.

Substitute S=4 in above equation.

4=\frac{D}{0.5}

D=0.5(4)

D=2

Hence, the required equation is D=0.5(4)

7 0
4 years ago
Suppose that a storm front is traveling at 33 mph. When the storm is 13 miles away a storm chasing van starts pursuing an averag
kramer

Answer:

= 15mins 18 seconds. The storm chaser van drove 13.53 miles to catch up with the storm which obviously has moved less than 0.53 miles as it was same time but multiplied below by 0.5 per minute as speed per minute is 0.5 for the storm. See right at the end the storm only moved 1.11 mile.

Step-by-step explanation:

We count in 1 minutes

54 mph = 54/60 = 0.9 miles per minute

Storm = 13 m +  1 minute  is;

33/60 = 0.55 miles = 11/20

M = (16 7/10 * 9/10x) = ( 3 7/10 * 11/20y ) +13

M = 15 3/10x = ( 407/200y +13)       (407/200 = y starting value +13)

M = 15 3/10x =  15 3/10 = 16 7/10x (the same as 16 7/10* 9/10 for x)

M = 15 3/10 x = 15 3/10  = 15.03    

M = 16 7/10x  / 9/10y                      (is also the same as 186/1000)

X = 185⁄1000 = 37⁄200xy x 16 7/10  (as starting value)

7/10 of 60 = 42 minutes

3/10 of 60 = 18 minutes

x = 15 mins 18 seconds.

y = 15 mins  18 seconds.

as 0.005 left over for y 3/10 was actually 15.035 gives us 0.005 of 60 can not be rounded up to a second.

However as we started with 16mins and 7/10 we can see that we multiplied by 9/10 so when we divide 16 7/10 by 9/10 we find  185⁄1000 = 37⁄200

To equal the mileage of the storm of where we multiplied 3 7/10 by 17/10

= 37/200 just the same

We added 13 miles of the storm to find each was multiplied by the larger x sum 9/10 and y was multiplied  

As 35/200 + 13 =  

13 37/200  

37/200 of 60 = 11.1 = 11.06 minutes which is

= 15.04 % more for y as 13 + 2 mins + 06 seconds = 15.06 = 15.035

The percentage looks the same but valued different as 2 of 13 as a percentage is multiplied as 13 x 15.04%  to equal the 2 of 15 miles as 15.04%.

To find how many miles we go back and see 15.035 = 15 7/200

Then we multiply this by 0.9 miles for the storm van

= 15 7/200 x 0.9 = 13.5315 = 13.53 miles

For the storm itself we can prove 0.53  increase of mileage

417/200 x 0.53 = 1.10505 = 1.11 miles. rounded up

5 0
4 years ago
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