Pls help I'm so dumb
1 answer:
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Answer:
The largest even integer is 0
Step-by-step explanation:
Given as :
The sum of four consecutive even number = - 12
Let The first even number = 2 x
The second even number = (2 x + 2)
The third even number = (2 x + 4)
The fourth even number = (2 x + 6)
<u>According to question</u>
sum of four consecutive even number = - 12
Or, 2 x + (2 x + 2) + (2 x + 4) + (2 x + 6) = - 12
Or, (2 x + 2 x + 2 x + 2 x) + (2 + 4 + 6) = - 12
Or, 8 x + 12 = - 12
Or, 8 x = - 12 - 12
Or, 8 x = - 24
∴ x =
i.e x = - 3
now, putting the value of x
The first even number = 2 × - 3 = - 6
The second even number = (2 × - 3 + 2) = - 6 + 2 = - 4
The third even number = (2 × - 3 + 4) = - 6 + 4 = - 2
The fourth even number = (2 × - 3 + 6) = - 6 + 6 = 0
So, The largest even integer = 0
Hence, The largest even integer is 0 Answer
Let 
be the tickets that the adults bought, and
be the tickets that children bought.
From the problem we have the system of linear equations:
The first thing we are going to do to solve our system, is replacing equation (2) in equation (1), and then, solve for
Now that we have the number of tickets that the adults bought, lets replace that value in equation (2):
Last but not least, to find the total number of tickets, we are going to add and 
:
We can conclude that <span>Northwest High School's senior class sold 632 raffle tickets.</span>
From the problem we have the system of linear equations:
The first thing we are going to do to solve our system, is replacing equation (2) in equation (1), and then, solve for
Now that we have the number of tickets that the adults bought, lets replace that value in equation (2):
Last but not least, to find the total number of tickets, we are going to add
We can conclude that <span>Northwest High School's senior class sold 632 raffle tickets.</span>