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3 years ago

Rearrange so that there is no zero or negative exponent. 2m^0 n^-4

Mathematics

2 answers:

Anni [7]3 years ago

7 0

Answer:

Step-by-step explanation:

2m^0*n^-4

=2*1*1/n^4

=2/n^4

Note:Any base that has it's power 0 is always considered as one .

If any base has negative exponent transfer that pase to the denominator then its power will be positive. For exanple:

4^-x

= $\frac{1}{4^x}$

uranmaximum [27]3 years ago

3 0

Answer:

2/n^4

Step-by-step explanation:

Anything to the zero power will become 1 so the m^0 will be 1 and that leaves just 2 in its place. Anything to a negative exponent is equal to its reciprocal so n^-1= 1/n^4. Then you multiple what remains, (2 x 1/n^4) to get the above answer.

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Answer:

$\frac{1}{2}$

Step-by-step explanation:

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3 years ago

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4 years ago

A computer can be classified as either cutting dash edge or ancient. Suppose that 86% of computers are classified as ancient.

andrezito [222]

Answer:

(a) The probability that both computers are ancient is 0.7396

(b) The probability that all seven computers are ancient is 0.3479

(c) The probability that at least one of seven randomly selected computers is cutting dash edge is 0.6520.

Because the probability is about 65% is it not unusual that at least one of seven randomly selected computers is cutting dash edge, it's more likely than not.

Step-by-step explanation:

We know that 86% of computers are classified as ancient. This means, if one computer is chosen at random, there is an 86% chance that it will be classified as ancient.

$P(ancient)=0.86$

(a) To find the probability that two computers are chosen at random and both are ancient you must,

The probability that the first computer is ancient is $P(ancient)=0.86$ and the probability that the second computer is ancient is $P(ancient)=0.86$

These events are independent; the selection of one computer does not affect the selection of another computer.

When calculating the probability that multiple independent events will all occur, the probabilities are multiplied, this is known as the rule of product.

Let A be the event "the first computer is ancient" and B the event "the second computer is ancient".

$P(A\:and \:B)=P(A)\cdot P(B)=0.86\cdot 0.86=0.86^2= 0.7396$

(b) To find the probability that seven computers are chosen at random and all are ancient you must,

Following the same logic in part (a) we have

Let A be the event "the first computer is ancient",

B the event "the second computer is ancient",

C the event "the third computer is ancient",

D the event "the fourth computer is ancient",

E the event "the fifth computer is ancient",

F the event "the sixth computer is ancient", and

G the event "the seventh computer is ancient"

$P(A\:and \:B\:and \:C\:and \:D\:and \:E\:and \:F\:and \:G)=\\P(A)\cdot P(B)\cdot P(C)\cdot P(D)\cdot P(E)\cdot P(F)\cdot P(G) =(0.86)^7=0.3479$

(c) To find the probability that at least one of seven randomly selected computers is cutting dash edge you must

Use the concept of complement. The complement of an event is the subset of outcomes in the sample space that are not in the event.

Let C the event "the computer is cutting dash edge".

Let A the event "the seven computers are ancient".

$P(C)=1-P(A)=1-0.3479=0.6520$

Because the probability is about 65% is it not unusual that at least one of seven randomly selected computers is cutting dash edge, it's more likely than not.

5 0

3 years ago

What equation passes through the point (4,3) and is perpendicular to the y-axis

Ksju [112]

Answer:

y=3

Step-by-step explanation:

perpendicular line to Y-axis passing through any point (m,n) is of the form

y=n

so the answer is

y=3

8 0

3 years ago

Find the area of the figure to the nearest tenth

schepotkina [342]

Answer:

Step-by-step explanation:

This is a sector of a circle measuring 140° and the circle has radius 9 inches.

We can use the formula for the area sector of a circle to figure this out.

Area of a Sector of a Circle = $\frac{\theta}{360}*\pi r^2$

Where

$\theta$ is the intercepted angle (here it is 140), and

r is the radius (here it is 9)

<em>plugging into the formula, we get:</em>

<em> $A=\frac{\theta}{360}*\pi r^2\\=\frac{140}{360}*\pi (9)^2\\=\frac{7}{18}*81\pi\\=98.96$ </em>

rounding to nearest tenth, it is 99.0 inches squared.

Option A is right.

7 0

4 years ago