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postnew [5]
3 years ago
12

The sum of a positive number and a negative number is positive when...

Mathematics
1 answer:
anyanavicka [17]3 years ago
4 0
When the absolute value of the positive number is higher than the absolute value of the negative number.
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A pole that is 3.2m tall casts a shadow that is 1.75m long. At the same time, a nearby tower casts a shadow that is
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2 years ago
Read 2 more answers
HELP!!!
olga55 [171]

Answer:

  a) 236/100 = 2.36

  b) 101/100 = 1.01

  c) 814/100 = 8.14

Step-by-step explanation:

The divisor in each case is already a factor of 100, so multiply the numerator and denominator by the number that will make the denominator 100. Then add 100 times the integer to the numerator of the fraction.

a) 2 9/25 = (200 +9·4)/(25·4) = 236/100 = 2.36

b) 1 1/100 = (100 +1)/100 = 101/100 = 1.01

c) 8 7/50 = (800 +7·2)/(50·2) = 814/100 = 8.14

____

Since each of these fractions has a denominator of 100, the decimal can be written by putting the least significant digit of the numerator in the hundredths place of the decimal number.

For example, for 236/100, putting 6 in the hundredths place puts 3 in the tenths place and 2 in the units place for a decimal number of 2.36.

5 0
3 years ago
Emma ran 3 miles in 27 minutes how long would it take her to run 5 miles?
Marizza181 [45]
It will take her 45 minutes to run 5 miles,because 27/3=9 and 9•5=45
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2 years ago
PLZ help me fast 2 mins left
jek_recluse [69]

Answer:

\sqrt{-5}=i\sqrt{5}

\sqrt{-25}=5i

Step-by-step explanation:

i is an imaginary unit, this means

i^2=-1

Rewrite -5 as 5\cdot (-1)=5\cdot i^2,

then

\sqrt{-5}=\sqrt{5i^2}=\sqrt{5}\cdot \sqrt{i^2}=\sqrt{5}\cdot i=i\sqrt{5}

Rewrite -25 as -25=25\cdot (-1)=25\cdot i^2,

then

\sqrt{-25}=\sqrt{25\cdot i^2}=\sqrt{25}\cdot \sqrt{i^2}=5\cdot i=5i

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2 years ago
Which of the following expressions can you multiply using the FOIL Method? Check all that apply. Please Hurry. 50 points!!
Helen [10]

Answer: the answers are

(x+a)(x-b)

(3x-2)(x+4)

Step-by-step explanation: i took the test and got it right hope this helps!

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2 years ago
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