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Stolb23 [73]
3 years ago
10

The volleyball team raised $350 from its fundraiser. It wants to buy jerseys and volleyballs. The jerseys cost $12 each, and the

team needs 22 jerseys. Volleyballs cost $15 each. What is the maximum number of volleyballs the team can buy and still have money left? Write your answer and explain the steps you took.
Mathematics
2 answers:
matrenka [14]3 years ago
7 0

The team can buy 5 volleyballs. I wrote the inequality (12)(22) + 15n < 350, then did the multiplication first. I used the subtraction and division properties of inequality to isolate the variable to find that n is less than about 5.73. I rounded down to 5, since you can’t buy part of a volleyball.

uysha [10]3 years ago
5 0
You have to set up an equation so 12 x 22 + 15v=
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OlgaM077 [116]

Answer:

The eastbound train travels at 92 mph and the westbound train travels at 96 mph.

Step-by-step explanation:

We know that Velocity = distance / time

If the eastbound train travels at x miles per hour, the westbound train travels at x + 4 mph.

After 3.5 hours, they are 658 miles apart. If we solve for distance the formula given above we have: Distance = velocity x time. We have that the total distance between both trains is 658 miles.

Substituting the values of the problem and solving for x we have

658 = 3.5x+3.5(x+4)\\658=3.5x+3.5x+14\\644=7x\\92=x

Thus, the eastbound train travels at 92 mph and the westbound train travels at 96 mph.

6 0
4 years ago
The design is rotated about the line x=1 to produce the shape of the urn. Finish the potter's design by drawing a picture
VLD [36.1K]

Answer:

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Step-by-step explanation:

5 0
2 years ago
I dont understand it (7×5)+(6×4)
Levart [38]

59

Step-by-step explanation:

7 × 5 = 35

6 × 4 = 24

35 + 24 = 59

because 4 + 5 is 9 and 3 + 2 is 5

so 59

3 0
3 years ago
Read 2 more answers
Find 2x2 - 2z4 + y2 - x2 + z4 if x = -4, y = 3, and z = 2.
Alexxandr [17]
X = - 4;  y = 3;  z = 2;
2 x² - 2 z^4 + y² - x² + z^4 =
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8 0
3 years ago
Find the length of midsegment YZ in trapezoid ABCD when A(-5,-6) B(-6,-2) C(-4,0) and D(3,2)
Luda [366]

Answer:

Option C

Step-by-step explanation:

Since, Y and Z are the midpoints of sides AB and CD of the given trapezoid.

Segment YZ will the midsegment of trapezoid ABCD.

By the theorem of midsegment,

m(YZ) = \frac{1}{2}(AD+BC)

By using expression for the length of a segment between two points,

Length of a segment = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance between two points A(-5, -6) and D(3, 2),

AD = \sqrt{(3+5)^2+(2+6)^2}

AD = \sqrt{64+64}

AD = \sqrt{128}

AD = 8\sqrt{2}

Distance between B(-6, -2) and C(-4, 0)

BC = \sqrt{(-6+4)^2+(-2-0)^2}

BC = \sqrt{8}

BC = 2\sqrt{2}

Therefore, m(YZ) = \frac{1}{2}(8\sqrt{2}+2\sqrt{2})

                             = \frac{1}{2} (10\sqrt{2})

                             = 5\sqrt{2}

Option C will be the answer.

7 0
3 years ago
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