Solving a system of equations, we will see that there are 6000 kg of coal on the pile.
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How many kilograms of coal are in the pile of coal?</h3>
Let's say that there are N kilograms of coal, and it is planned to burn it totally in D days, these are our variables.
We know that:
- If the factory burns 1500 kilograms per day, it will finish burning the coal one day ahead of planned.
- If it burns 1000 kilograms per day, it will take an additional day than planned.
Then we can write the system of equations:
(1500)*(D - 1) = N
(1000)*(D + 1) = N
Because N is already isolated in both sides, we can write this as:
(1500)*(D - 1) = N = (1000)*(D + 1)
Then we can solve for D:
(1500)*(D - 1) = (1000)*(D + 1)
1500*D - 1500 = 1000*D + 1000
500*D = 2500
D = 2500/500 = 5
Now that we know the value of D, we can find N by replacing it in one of the two equations:
(1500)*(D - 1) = N
(1500)*(5 - 1) = N
(1500)*4= N = 6000
This means that there are 6000 kilograms of coal on the pile.
If you want to learn more about systems of equations:
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Well, should be likee thiss correct meh if im wrong or what ever, but
the answer would be, last one (x + 8)(x - 8), well 1, is because the 64 is a negative so if you would just take that 64 and bring it down then look at this onece the work is donee then when u add the 2 numbers that x would be x² or x2 n that - 64 is that + 8 (-8) witch would equal out so if you really look at it the CORRECT ANSWER WOULD BE B. (x - 8)(x -8)
i realli understand if youu don't then comment in the sec beloww↓
Answer:
...
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since they give us the side opposite of the given angle(Opposite) and we are trying to find for a (Adjacent/side), so we use TOA
tan(30)= 
i see u dont want it solved but ill solve it anyways
since a is on the bottom then lets switch them

x= 6.928
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Its y=1/2x +2(the second one)
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