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3 years ago

One third plus two fifths

Mathematics

2 answers:

Mekhanik [1.2K]3 years ago

7 0

Find common denominators. What you multiply to the denominator, you multiply to the numerator

1/3(5/5) = 5/15

2/5(1/3) = 2/15

5/15 + 2/15 = 7/15

7/15 is your answer

hope this helps

notsponge [240]3 years ago

4 0

When having you have to turn the words into numbers which is 1/3+2/5. Then you find a denominator which is 15. Next using the same number that multiply for the denominator you multiply the numerator, combining all those step you are left will 5/15+6/15. Then you add 5/15 to 6/15 to get 11/15 which is the answer.

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Hello there!

We are given the function:

$\displaystyle \large{ f(x) = | - 2x| - 3} \\$

To find the range, we know that domain is the set of all x-values and also called 'input' while range is the set of all y-values and also called 'output'.

Basic Function - you add the input, you get the output. You add x-value in a function, you get y-value. You add domain, you get range.

So, we substitute x = 1,2 and 3 in the function.

x = 1

$\displaystyle \large{ f(1) = | - 2(1)| - 3} \\ \displaystyle \large{ f(1) = | - 2| - 3} \\$

Recall that any numbers in absolute value are always positive.

$\displaystyle \large{ f(1) = 2 - 3} \\ \displaystyle \large{ f(1) = - 1} \\$

x = 2

$\displaystyle \large{ f(2) = | - 2(2)| - 3} \\ \displaystyle \large{ f(2) = | - 4 | - 3} \\ \displaystyle \large{ f(2) = 4 - 3} \\ \displaystyle \large{ f(2) = 1}$

x = 3

$\displaystyle \large{ f(3) = | - 2(3)| - 3} \\ \displaystyle \large{ f(3) = | - 6| - 3} \\ \displaystyle \large{ f(3) = 6 - 3} \\ \displaystyle \large{ f(3) = 3}$

Therefore, Range: {-1,1,3}

Let me know if you have any questions!

Topic: Absolute Value Function / Modulus Function

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