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Kitty [74]
3 years ago
7

Write an equation that is parallel to the line y=3x-5 and passes through the point (-1,2)

Mathematics
1 answer:
ryzh [129]3 years ago
6 0
Two lines with same slopes are parallel.
So The slope must be 3.
2=3(-1)+a
a=5
y=3x+5
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F(x) = x2 – 2x - 8
maw [93]

Answer:

The y-intercept is the point (0,-8)

see the attached figure

Step-by-step explanation:

we have

f(x)=x^{2}-2x-8

we know that

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so

For x=0

f(x)=0^{2}-2(0)-8\\f(x)=-8

therefore

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see the attached figure to better understand the problem

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Answer:

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Step-by-step explanation:

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Nady [450]

Answer:

  • (1,3) is inside the triangle

Step-by-step explanation:

Orthocenter is the intersection of altitudes.

We'll calculate the slopes of the two sides and their altitudes ad find the intersection.

<h3>Side QR</h3>
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<u>Perpendicular slope:</u>

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<u>Perpendicular line passes through S(-1, -2):</u>

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<h3>Side RS</h3>
  • m = (-2 - 3)/(-1 -4) = -5/-5 = 1

<u>Perpendicular slope:</u>

  • -1/m = -1/1 = -1

<u>Perpendicular line passes through Q(-1, 5):</u>

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The intersection of the two lines is the orthocenter.

<u>Solve the system of equations to get the coordinates of the orthocenter:</u>

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<u>Find y-coordinate:</u>

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The orthocenter is (1, 3)

If we plot the points, we'll see it is inside the triangle

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