Because there are 4 students who passed in all subjects, we can say that only 2 students passed in English and Mathematics only, only 3 students passed in Mathematics and Science only, and no one passed in English and Science only.
Given that we have deduced the number of students who passed in two subjects, we can now solve for the number of students who passed only one subject.
English = 15 - (4 + 2 + 0) = 9
Mathematics = 12 - (4 + 3 + 2) = 3
Science = 8 - (4 + 3 + 0) = 1
1. In English but not in Science,
9 + 2 = 11
2. In Mathematics and Science but not in English
3 + 3 + 1 = 7
3. In Mathematics only
= 3
3. More than one subject only
3 + 4 + 2 + 9 = 18
It will really be helpful if you draw yourself a Venn Diagram for this item.
9514 1404 393
Answer:
14.01, 493, 87
Step-by-step explanation:
Subtracting 28 from both sides tells you the range of values you need to be looking at.
28 + x > 42
x > 14
Any values more than 14 will make the inequality true. Three of them are ...
14.01, 493, 87
Answer:
m<FAB = 75°
m<BAC = 105°
Step-by-step explanation:
First, find the value of x.
(13x - 3)° = (3x + 2)° + 55° (exterior angle theorem of a ∆)
Solve for x
13x - 3 = 3x + 2 + 55
13x - 3 = 3x + 57
Collect like terms
13x - 3x = 57 + 3
10x = 60
Divide both sides by 10
x = 6
✔️m<FAB = 13x - 3
Plug in the value of x
m<FAB = 13(6) - 3 = 78 - 3
m<FAB = 75°
✔️m<BAC = 180 - m<FAB (angles on a straight line/supplementary angles)
m<BAC = 180 - 75 (substitution)
m<BAC = 105°
Answer:

Step-by-step explanation: