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natta225 [31]
3 years ago
7

Adam takes a loan of $8,250 at a 7% simple rate for 5 years. How much will be paid after 3 years? how much interest will be paid

in total for the loan?
Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
6 0
$4,950 will be paid after 3 years.
$577.50 will be paid as interest for the total loan.
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A lifeguard received 15 hours of first aid training and 10 hours of cardiopulmonary resuscitation training what is the ratio of
aivan3 [116]

Answer:

The ration of 15 to 10 is 3/2

Step-by-step explanation:

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2 years ago
A triangle has an area of 35 square inches. the length of one of the sides it 10 inches. what is the length of the perimeter? in
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The perimeter would be about 34.4 because if you choose the bottom side to be ten, by multiplying 35 by 2 to get 70 you can divide by 10 to get 7. Since you know the height and width, you can use pythagorean theorem, a^2 + b^2 = c^2. Plug in the numbers you have 10^2+7^2=c^2. c^2=149, so if you square root 149 you will get a irrational number but when rounded you get 12.2- so that is one side multiply by 2 and get 24.4- and add 10 to get 34.4
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2 years ago
Which function has the greatest rate of exponential growth?
Veronika [31]

Answer:

C

Step-by-step explanation:

Here, we want to find which of the expressions have the greatest rate of exponential growth.

The easiest way to go about this is have a substitution for the term t;

Let’s say t = 6

Thus;

h(t) = 1.18^1 = 1.18

K(t) = 0.375^6 = 0.002780914307

f(t) = 1.36^6 = 6.327518887936

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Another way to find this is to express each as a sum of 1

f(t) = (1+ 0.36)^t

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k(t) = (1-0.625)^t

We can see clearly that out of all the terms in the brackets asides 1, 0.36 is the biggest in value

4 0
3 years ago
Charlie bought a pair of shorts at the store when they were having a 45% off sale.If the regular price of the pair of shorts was
nekit [7.7K]

Charlie would have to pay 10 dollars






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3 years ago
Read 2 more answers
Plsss answer, don’t need too show any work
Dovator [93]
Hey! The answer is 60 :)
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2 years ago
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