Answer:
93 = g + 36 + 18
Step-by-step explanation:
1) We calculate the volume of a metal bar (without the hole).
volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²
Volume=(0.935 m²)(2 m)=1.871 m³
2) we calculate the volume of the parallelepiped
Volume of a parallelepiped= area of the section x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³
3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar - volume of a parallelepiped
Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³
4) we calculate the mass of the metal bar
density=mass/ volume ⇒ mass=density *volume
Data:
density=8.10³ kg/m³
volume=1.551 m³
mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg
answer: The mas of the metal bar is 12.408x10³ kg or 12408 kg
Answer:
20 gmaes in all
Step-by-step explanation:
14/x = 70%
x = 14/70%
Answer:
B.
Step-by-step explanation:
All computer simulations are designed to test a large number of different scenarios with various sets of data in order to understand each output that certain data generates and ultimately find the best solution. This is the overall main reason why simulations are created. The same applies in this scenario, this simulation will be used to test hypotheses about patterns in the job placement process that are costly or time-consuming to observe in reality. If such tests had to be conducted by actual people it would take months, years, or even decades to generate and analyze all the data.
Answer: It looks correct to me !
Step-by-step explanation:
