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stiks02 [169]
3 years ago
9

What is the vertex of the absolute value function defined by ƒ(x) = |x - 7| + 1?(

Mathematics
1 answer:
Lena [83]3 years ago
6 0
The vertex of function y = |x| is (0; 0).
We have: f(x) = |x - 7| + 1
shift the graph of the function y = |x| 7 units right and 1 unit up. Then the vertex of function f is (7; 1).
Your answer is A. (7; 1)
Look at the picture.

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A drill is used to dig down into the earth. After 2 hours, the drill is 12 meters below the surface. After 5 hours, the drill is
mojhsa [17]

Answer:

6y = x

Step-by-step explanation:

All that equation is saying is that for every 1 hour drilled (x), 6 meters (y) are drilled.

y = distance in meters

x = time

12y = 2x

12y/2 = 2x/2

6y = x

30y = 5x

30y/5 = 5x/5

6y = x

5 0
4 years ago
4. A group of friends rents a boat to spend an afternoon on a lake. The boat rental has a flat fee of $180 for up to three hours
OverLord2011 [107]

Answer:

it is D c= 180 + 50h + 20p

Step-by-step explanation:

c is the total cost and the boat is 180 but for additional hour it would be +$50

now the first four passenger is free but if another person comes on then it would be +$20 hope this help

5 0
4 years ago
There are 4 red balls, 6 white balls, and 3 green balls in a bag. If one ball is drawn from the bag at random, what is the proba
nika2105 [10]

Answer:

A

Step-by-step explanation:

i think its A because we have all balls together <em><u>1</u></em><em><u>3</u></em>. Problem is asking about <em><u>6</u></em><em><u> </u></em><em><u>w</u></em><em><u>h</u></em><em><u>i</u></em><em><u>t</u></em><em><u>e</u></em> balls, that's why is 6/13:)

3 0
3 years ago
Read 2 more answers
Use the t-distribution to find a confidence interval for a difference in means μ1-μ2 given the relevant sample results. Give the
Serggg [28]

Answer:

(a) The best estimate of \mu_{1}-\mu_{2} is 13.2.

(b) The margin of error is 5.30.

(c) The 95% confidence interval for the difference between two means is (7.90, 18.50).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means using a <em>t</em>-interval is:

CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2, (n_{1}+n_{2}-2)} \sqrt{S_{p}^{2}[\frac{1}{n_{1}}+\frac{1}{n_{2}}]}}

(a)

A point estimate of a parameter (population) is a distinct value used for the estimation the parameter (population). For instance, the sample mean \bar x is a point-estimate of the population mean μ.

Similarly the point estimate of the difference between two means is:

\bar x_{1}-\bar x_{2}

Compute the point estimate of \mu_{1}-\mu_{2} as follows:

E(\mu_{1}-\mu_{2})=\bar x_{1}-\bar x_{2}\\=79.0-65.8\\=13.2

Thus, the best estimate of \mu_{1}-\mu_{2} is 13.2.

(b)

Compute the pooled variance as follows:

S_{p}^{2}=\frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2}=\frac{(35-1)10.5^{2}+(20-1)7.2^{2}}{35+20-2}=89.311

Compute the critical value of <em>t</em> as follows:

t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.05/2, (35+20-2)}=t_{0.025, 53}=2.00

*Use a <em>t</em>-table.

Compute the margin of error as follows:

MOE=t_{\alpha/2, (n_{1}+n_{2}-2)} \sqrt{S_{p}^{2}[\frac{1}{n_{1}}+\frac{1}{n_{2}}]}}

          =2.00\times\sqrt{89.311\times [\frac{1}{35}+\frac{1}{20}]} \\=5.298\\\approx5.30

Thus, the margin of error is 5.30.

(c)

Compute the 95% confidence interval for the difference between two means as follows:

CI=(\bar x_{1}-\bar x_{2})\pm MOE

      =13.2\pm 5.298\\=(7.902, 18.498)\\\approx (7.90, 18.50)

Thus, the 95% confidence interval for the difference between two means is (7.90, 18.50).

4 0
4 years ago
PLZZZZZZZZZZZ HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Luda [366]

Answer:

Step-by-step explanation:

Your first step is to figure out which variable you want to cancel out.

Luckily, all these problems have x or y already set up to eliminate.

You can find these variables because they are opposite signs of each other, such as -x and x

Add the y's together and the #'s on the other side together, then solve to find the 2nd variable. Once you find one, you can plug that answer into the easier of the two equations and solve for the other variable.

8 0
2 years ago
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