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stiks02 [169]
3 years ago
9

What is the vertex of the absolute value function defined by ƒ(x) = |x - 7| + 1?(

Mathematics
1 answer:
Lena [83]3 years ago
6 0
The vertex of function y = |x| is (0; 0).
We have: f(x) = |x - 7| + 1
shift the graph of the function y = |x| 7 units right and 1 unit up. Then the vertex of function f is (7; 1).
Your answer is A. (7; 1)
Look at the picture.

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If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?
lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

3x^2-(3k-2)x-(k-6) \text{ with }k=2:

3x^2-(3\cdot 2-2)x-(2-6)

3x^2-4x+4

I'm going to solve 3x^2-4x+4=0 for x using the quadratic formula:

\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}

\frac{4\pm \sqrt{16-16(3)}}{6}

\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}

\frac{4\pm 4\sqrt{-2}}{6}

\frac{2\pm 2\sqrt{-2}}{3}

\frac{2\pm 2i\sqrt{2}}{3}

Let's see if uv=u+v holds.

uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}

Keep in mind you are multiplying conjugates:

uv=\frac{1}{9}(4-4i^2(2))

uv=\frac{1}{9}(4+4(2))

uv=\frac{12}{9}=\frac{4}{3}

Let's see what u+v is now:

u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}

u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}

We have confirmed uv=u+v for k=2.

4 0
2 years ago
out of 24 students, 6 preferred to use pastels for their portraits while 4 preferred to use watercolours watercolours. what perc
notka56 [123]

Answer:

4% used pastels.

Step-by-step explanation:,,

green is the most

5 isnt blue.green,yello or red

3 0
3 years ago
To equation solve 8 = h/-3 +19
Naya [18.7K]
8h/3+19
Move all terms to the left
8-(h/3+19)=0
Get rid of parentheses
-h/3-19+8=0
Multiply all terms by denominator
-h-19*3+8*3=0
Add all numbers and variables together
-1h-33=0
Move all terms containing h to the left all other terms to the right
-h=33
h=33/-1
h=-33
6 0
3 years ago
What’s the correct answer for this?
Deffense [45]

Answer:

The first option

Step-by-step explanation:

In the image, we can notice that NQ is longer than PQ, similar to how JH is longer than NJ. Thus, NQ must be aligned with JH and PQ with JN. As PN and HN are clearly the longest for each triangle, those must be aligned as well.

All of the responses have NP and NH aligned.

The last response does not have NQ aligned with JH.

The second and third do not align PQ and JN.

The first option is our answer.

6 0
3 years ago
The first step to solve the equation x/4-3/4=16 is shown below
Sladkaya [172]

Answer:

i think it is A because that seems like the one making the most sense

Step-by-step explanation:

7 0
3 years ago
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