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3 years ago

What is the vertex of the absolute value function defined by ƒ(x) = |x - 7| + 1?(

Mathematics

1 answer:

Lena [83]3 years ago

6 0

The vertex of function y = |x| is (0; 0).
We have: f(x) = |x - 7| + 1
shift the graph of the function y = |x| 7 units right and 1 unit up. Then the vertex of function f is (7; 1).
Your answer is A. (7; 1)
Look at the picture.

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I need help with #2 (click the attached photo to view properly)<br>I will mark Branliest

Shtirlitz [24]

Hi there! :)

$\large\boxed{j(h(x))(2) = 31}$

Solve for j(h(x)):

h(x) = x² + 4

j(x) = 4x - 1

Substitute in h(x) into "x":

j(h(x)) = 4(x² + 4) - 1

j(h(x)) = 4x² + 16 - 1

j(h(x)) = 4x² + 15

Solve at x = 2:

4(2)² + 15 = 4(4) + 15 = 31.

7 0

3 years ago

steve has 500 more marbles than richard at first. he gives 300 marbles to richard. who has more marbles now, and by how many?

Yakvenalex [24]

Steve has x+500 marbles
richard has x marbles

if steve gives richard 300 marbles then
x+500-300 x+300
so x+200 and x+300
richard has more and by 100

8 0

3 years ago

Read 2 more answers

Solve the equation : 3x - 2 = 4x + 5<br>How many solutions are there?

Nookie1986 [14]

Answer:

one solution

Step-by-step explanation:

Given

3x - 2 = 4x + 5 ( subtract 4x from both sides )

- x - 2 = 5 ( add 2 to both sides )

- x = 7 ( multiply both sides by - 1 )

x = - 7 ← the one solution

8 0

3 years ago

Read 2 more answers

Question Down below.

expeople1 [14]

Answer:

there equal

Step-by-step explanation:

the absolute value of 3 is 3

and the absolute value of -3 is 3

hope this helps

let me know if you need help with anymore

Have a great day!

8 0

3 years ago

Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes and one vertex in t

Tresset [83]

Answer: The volume of largest rectangular box is 4.5 units.

Step-by-step explanation:

Since we have given that

Volume = $xyz$

with subject to $x+2y+3z=9$

So, let $z=\dfrac{9-x-2y}{3}$

So, Volume becomes,

$V=xyz\\\\V=xy(\dfrac{9-x-2y}{3})\\\\V=\dfrac{9xy-x^2y-2xy^2}{3}$

Partially derivative wrt x and y we get that

$9-2x-2y=0\implies 2x+2y=9\\\\and\\\\9-x-4y=0\implies x+4y=9$

By solving these two equations, we get that

$x=3,y=\dfrac{3}{2}$

So, $z=\dfrac{9-x-2y}{3}=\dfrac{9-3-3}{3}=\dfrac{3}{3}=1$

So, Volume of largest rectangular box would be

$xyz=3\times \dfrac{3}{2}\times 1=\dfrac{9}{2}=4.5$

Hence, the volume of largest rectangular box is 4.5 units.

4 0

3 years ago