Find the distance between the points , 5−7 and , 56 .

Graph the inequality.<br> -6 ≤y + 2x < 15

omeli [17]

Inequalities help us to compare two unequal expressions. The correct option is B.

<h3>What are inequalities?</h3>

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed. It is mostly denoted by the symbol <, >, ≤, and ≥.

The given inequality -6 ≤y + 2x < 15 can be broken into two small inequality, as shown below.

-6 ≤y + 2x
y + 2x < 15

Now, if we plot the inequality as shown below, then the area in which both the shaded region overlap is the area of the this inequality.

Hence, the correct option is B.

Learn more about Inequality:

brainly.com/question/19491153

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6 0

2 years ago

Jonathan bought a calculator for X$. Cindy bought the same calculator for 3 times more than Jonathan paid for his calculator. Wh

Andrej [43]

Answer:

3x or 3*x

Step-by-step explanation:

5 0

2 years ago

Please help this is a 30 60 90 triangle

natka813 [3]

Answer:

See below

Step-by-step explanation:

$x = \frac{1}{2} \times \sqrt{6} \\ \\ x = \frac{ \sqrt{6} }{2} \\ \\ y = \frac{ \sqrt{3} }{2} \times \sqrt{6} \\ \\ y = \frac{ \sqrt{3 \times 6} }{2} \\ \\ y = \frac{ \sqrt{18} }{2} \\ \\ y = \frac{ 3\sqrt{2} }{2}$

8 0

2 years ago

Read 2 more answers

Which of the equations below could be the equation of this parabola?

Aleonysh [2.5K]

Answer:

C. x=-3y^2

Step-by-step explanation:

The group of parabola opens left so, x=ay^2

parabola opens left so a in negative x=-3y^2

Hope it helps....

8 0

2 years ago

Determine whether the equation x^3 - 3x + 8 = 0 has any real root in the interval [0, 1]. Justify your answer.

nikdorinn [45]

Answer:

The equation does not have a real root in the interval $\rm [0,1]$

Step-by-step explanation:

We can make use of the intermediate value theorem.

The theorem states that if $f$ is a continuous function whose domain is the interval [a, b], then it takes on any value between f(a) and f(b) at some point within the interval. There are two corollaries:

If a continuous function has values of opposite sign inside an interval, then it has a root in that interval. This is also known as Bolzano's theorem.
The image of a continuous function over an interval is itself an interval.

Of course, in our case, we will make use of the first one.

First, we need to proof that our function is continues in $\rm [0,1]$ , which it is since every polynomial is a continuous function on the entire line of real numbers. Then, we can apply the first corollary to the interval $\rm [0,1]$ , which means to evaluate the equation in 0 and 1:

$f(x)=x^3-3x+8\\f(0)=8\\f(1)=6$

Since both values have the same sign, positive in this case, we can say that by virtue of the first corollary of the intermediate value theorem the equation does not have a real root in the interval $\rm [0,1]$ . I attached a plot of the equation in the interval $\rm [-2,2]$ where you can clearly observe how the graph does not cross the x-axis in the interval.

6 0

2 years ago