Answer:
what grade are u
Step-by-step explanation:
so that I c could definetly answer it
<h3>
Short Answer: Yes, the horizontal shift is represented by the vertical asymptote</h3>
A bit of further explanation:
The parent function is y = 1/x which is a hyperbola that has a vertical asymptote overlapping the y axis perfectly. Its vertical asymptote is x = 0 as we cannot divide by zero. If x = 0 then 1/0 is undefined.
Shifting the function h units to the right (h is some positive number), then we end up with 1/(x-h) and we see that x = h leads to the denominator being zero. So the vertical asymptote is x = h
For example, if we shifted the parent function 2 units to the right then we have 1/x turn into 1/(x-2). The vertical asymptote goes from x = 0 to x = 2. This shows how the vertical asymptote is very closely related to the horizontal shifting.
Answer:
Step-by-step explanation:
We need to find the height of the cylinder
pythagorean theorem
15 is the bottom leg (30/2=15)
17 is hypotonuse
b=height
15^2+b^2=17^2
225+b^2=289
minus 225 both sides
b^2=64
sqrt both sides b=8
Vcone=(1/3)hpir^2
d/2=r=30/2=15
h=8
V=(1/3)8pi15^2
V=(1/3)8pi225
V=8pi75
V=600pi
aprox pi=3.14159256
V=1884.955536 in^3
round if nececary
Based on the calculations, the scale factor for this dilation is equal to 1/3.
<h3>How to determine the scale factor for this dilation?</h3>
First of all, we would use the distance formula to find the length of side QR and Q'R' as follows:
Distance = √[(x₂ - x₁)² - (y₂ - y₁)²]
Substituting the given points into the formula, we have;
Distance QR = √[(5 - (-1))² + (0 - 0)²]
Distance QR = √[(5 + 1)² + (0)²]
Distance QR = √[6² + 0]
Distance QR = √36
Distance QR = 6 units.
For side Q'R', we have:
Distance Q'R' = √[(1 - (-1))² + (2 - 2)²]
Distance Q'R' = √[(1 + 1)² + (0)²]
Distance Q'R' = √[2² + 0]
Distance Q'R' = √4
Distance Q'R' = 2 units.
Now, the scale factor for this dilation is given by:
Scale factor = Q'R'/QR
Scale factor = 2/6
Scale factor = 1/3.
Read more on scale factor here: brainly.com/question/17079307
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