<h2>Solution:.</h2>
Let the ceilings be <em>a</em><em> </em><em>&</em><em> </em><em>b</em>
and the distance from one corner of the ceiling to the opposite be <em>c</em>
<em>then </em><em>using</em><em> </em><em>Pythagoras</em><em> theorem</em>

hence ,c .°. the distance from one corner of the ceiling to the opposite is<em> </em><em>2</em><em>0</em>
Let
x-------> the width of the rectangular area
y------> the length of the rectangular area
we know that
y=x+15------> equation 1
perimeter of a rectangle=2*[x+y]
2x+2y <= 150-------> equation 2
substitute 1 in 2
2x+2*[x+15] <=150--------> 2x+2x+30 <=150----> 4x <=150-30
4x <= 120---------> x <= 30
the width of the rectangular area is at most 30 ft
y=x+15
for x=30
y=30+15------> y=45
the length of the rectangular area is at most 45 ft
see the attached figure
the solution is<span> the shaded area</span>
Highly because they do not have to vacuum their car
Answer:
B and C
Step-by-step explanation:
Distribute
4x^2 + 10x = 4x^2 +10x
30x^4 - 12x^3 = 30x^4 - 12x^3