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3 years ago

Explain or show that the point (5,-4) is a solution to this system of equations

Mathematics

1 answer:

Harman [31]3 years ago

8 0

Answer:

You could substitute the point (5,-4) into each equation

Step-by-step explanation:

x=5 y=-4

3x-2y=23

3(5)-2(-4)=23

15+8=23

23=23

2x+y=6

2(5)+(-4)=6

10-4=6

6=6

The points go into each equation which proves that the point (5,-4) is the solution.

(i don't know if I did this right, I apologize if I didn't

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HELP HELP HELP HELP HELP HELP (STEP BY STEP)

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With some simple rearrangement, we can rewrite the numerator as

$2x^3 - 3x^2 - x + 4 = 2(x^3 - x) - 3x^2 + x + 4 \\\\ ~~~~~~~~ = 2x(x^2-1) - 3(x^2 - 1) + x + 1 \\\\ ~~~~~~~~ = (2x-3)(x^2-1) + x+1$

Then factorizing the difference of squares, $x^2-1=(x-1)(x+1)$ , we end up with

$\dfrac{2x^3 - 3x^2 - x + 4}{x^2 - 1} = \dfrac{(2x-3)(x-1)(x+1) + x+1}{(x-1)(x+1)} \\\\ ~~~~~~~~ = \boxed{2x-3 + \dfrac1{x-1}}$

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