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Sliva [168]
4 years ago
14

many colleges determine the number of full time students f,by using the formula f=n/15 where n is the total number of credits fo

r each semester if a student registers for 46140 credits how many full time students does the campus have. then what is the formula for n  n=
Mathematics
1 answer:
Cloud [144]4 years ago
7 0
"A student" doesn't register for 46,140 credits, unless he wants to be very very busy.

If ALL of the students on campus register for 46,140 credits, then many colleges
would estimate the number of full-time students by using the formula

f = n / 15 = 46,140 / 15 = <u>3,076</u> students.

That's not the formula for 'n'.  'n' is the total number of credits for the semester,
and the question tells you what 'n' is.  Knowing 'n', the formula helps you find 'f'.
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In Data Set A mean , standard deviation are better measure of center as they give more information about the center of  data.

In Data Set B mean , standard deviation are better measure of center as they give more information about thecenter of data.

Step-by-step explanation:

Data Set A           Data Set B

1                                   3

3                                   5

3                                   5

2                                   4

4                                    6

0                                    1

4                                     6

3                                     6

3                                      6

5                                      6

2                                     5

Mean of Set A= 1+3+3+2+4+0+4+3+3+5+2/ 11= 30/11= 2.7272

Median of Set A= 0,1,2,2,3,3 ,3,3,4,4,5

Median   ( the middle value)=3

Mode( the repeated value)= 3

Quartiles

1st Quartile= n/4 value= 30/4= 7.5 which lies between 4th and 5th value

3rd quartile= 3n/4= 90/4= 22.5 which lies between 10 th and 11th value

Range= highest value- lowest value= 5-0=5

Standard Deviation = 1.354

In this mean ,median, mode and standard deviation are better measure of center as they give more information about the data.

The range and quartiles are better measure of spread.

Mean of Set B= 3+5+5+4+6+1+6+6+6+6+5/11=53/11=4.81818

Median of Set B= 1,3,4,5,5,5,6,6,6,6,6

Median ( the middle value)= 5

Mode ( the repeated value)= 6

Quartiles

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3rd quartile= 3n/4= 159/4= 39.75 which lies between 9 th and 10 th value

Range= highest value- lowest value=6-1= 5

Standard Deviation= 1.5266

In this mean , standard deviation are better measure of center as they give more information about the data.

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Median:It is the  middle value when data is ordered from least to greatest.

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Range: Total spread is given by the range.

Standard deviation: How far a data point is from the mean.

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