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lora16 [44]
3 years ago
11

Please solve and explain your answer

Mathematics
1 answer:
zubka84 [21]3 years ago
7 0

I think this is right. you can ask your teacher about second one.

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Write an equation of a line parallel to line EF below in slope-intercept form that passes through the point (2, 6).
N76 [4]

Answer:

y = -⅔x + ²²/₃  

Step-by-step explanation:

1. Calculate the slope of EF

Assume E is at (-2, 5) and F is at (1, 3).

m₁ = (y₂ - y₁)/(x₂ - x₁) = (3 - 5)/(1 -(-2)) = -⅔

2. Calculate the slope of the parallel line

m₂ = m₁ = -⅔

3. Calculate its y-intercept

y = mx + b

6 =-⅔(2) + b

Simplify

6 = -⁴/₃ + b

Add ⁴/₃ to each side

b = 6 + ⁴/₃ = ¹⁸/₃ + ⁴/₃ = ²²/₃

The y-intercept is at (0,²²/₃).

4. Write the equation for the line

y = -⅔x + ²²/₃

The diagram shows EF in red. The parallel line in black passes through (2, 6) with a y-intercept at (0,²²/₃).

7 0
4 years ago
Please help with this algebra :)
Dahasolnce [82]
I am gonna go for D is the answer.
8 0
3 years ago
What is the product? startfraction 4 k 2 over k squared minus 4 endfraction times startfraction k minus 2 over 2 k 1 endfraction
Tcecarenko [31]

The product of the expression (\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1}  is the expression \frac{2}{k+2}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the expression:

(\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1} \\\\This\ can\ be\ simplified\ to:\\\\(\frac{2(2k+1)(k-2)}{(k+2)(k-2)(2k+1)}) \\\\=\frac{2}{k+2}

The product of the expression (\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1} is the expression \frac{2}{k+2}

Find out more on equation at: brainly.com/question/2972832

#SPJ4

7 0
2 years ago
Solve 3x2 + 4x = 2 in a quadratic formula
egoroff_w [7]

Answer:

x

=

−

2

±

√

10

3

Step-by-step explanation:

6 0
3 years ago
Which equation represents the graphed function?
gtnhenbr [62]

Answer:

the answer is A.

Step-by-step explanation:

the slope is 4 and the y-intercept is -2

4 0
3 years ago
Read 2 more answers
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