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4 years ago

I need to find the Greatest Common Factor of 16 and 36...I was confused on the question. Is it correct?

Mathematics

2 answers:

fenix001 [56]4 years ago

6 0

The greatest common factor: The way I learned it was: I took the number (in this case it's 16 and 36) I took 16 and listed out the numbers that go into 16 like:1, 2, 4, 8, and 16. You would do the same thing for 36. List out the numbers that go into that, and after that, you would find the biggest number that they have in common. I hunk that way is easier than the tree. We actually learned this a week ago, and I got an A+. I hope this helped! Good luck!

kogti [31]4 years ago

3 0

You were wrong, the correct answer is 4

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Timothy is filling fish bowls with pebbles at his fish store. He wants to have $\frac{1}{6}$ of a pound of pebbles in each fish

Luba_88 [7]

Answer:

Step-by-step explanation:

Given that:

Each fish bowl to have pebbles of weight equivalent to = $\frac{1}{6}$

Total pounds of pebbles that Timothy can use = $2\frac{1}{3}$

To find:

The greatest value of Total number of fish bowls that Timothy can fill ?

Solution:

First of all, we need to convert mixed fraction into a fractional number and then we also need to see division of two fractions.

Formula:

$1. \ p\dfrac{q}{r} = \dfrac{p\times r+q}{r}\\2. \ \dfrac{\frac{a}{b}}{\frac{c}d}=\dfrac{a\times d}{b\times c}$

Now, the given mixed fraction can be converted to fractional number as:

$2\dfrac{1}{3} = \dfrac{2\times 3+1}{3} = \dfrac{7}{3}$

Now, To find the total number of fish bowls that can be filled, we need to divide the total number of pounds with number of pounds of pebbles in each fish bowl.

So, the answer is:

$\dfrac{\frac{7}{3}}{\frac{1}{6}}\\\Rightarrow \dfrac{7\times 6}{3\times 1}\\\Rightarrow \dfrac{42}{3}\\\Rightarrow \bold{14}$

14 number of fish bowls can be filled.

3 0

3 years ago

A function of the form f(x) = mx + b, where m and b are real numbers, is called a _____

jasenka [17]

Answer:

A function of the form $f(x) = mx + b$ , where 'm' and 'b' are real numbers, is called a linear function.

Step-by-step explanation:

A linear function is one in which the $f(x)$ value of the function varies linearly with 'x'. When we plot a linear function on a graph, the resulting curve is always a straight line with the slope of the line being constant.

A linear function is of the form:

$f(x)=mx+b$ , where, 'm' and 'b' are real numbers.

The degree or the highest exponent of 'x' in a linear function is always equal to 1.

Therefore, a function of the form $f(x) = mx + b$ , where 'm' and 'b' are real numbers, is called a linear function.

4 0

3 years ago

Last one for this topic\

Eddi Din [679]

Answer:

Step-by-step explanation:

because if you do the math if you do 215 x 48 in doesn't reach to 12000 at all.

8 0

3 years ago

Read 2 more answers

What is the determinant of A = [ -2 2 -5 4 -1 -2 1 3 -5]

stepan [7]

Answer:

-51

Step-by-step explanation:

$\begin{vmatrix}-2&2&-5\\4&-1&-2\\1&3&-5\end{vmatrix}=\\=\mathsf{-10-4-60-5+40-12}=\\=\mathsf{-91+40}=\\=\mathsf{-51}$

5 0

3 years ago

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A procurement specialist has purchased 25 resistors from vendor 1 and 30 resistors from vendor 2. Let

Ulleksa [173]

Answer:

Normal Distribution

Standard error = 0.473

Step-by-step explanation:

We are given the following information:

A procurement specialist has purchased 25 resistors from vendor 1 are assumed to be normally distributed with mean 100 ohms and standard deviation 1.5 ohms.

$x_{1,1}, x_{1,2}, ... , x_{1,25}\\\mu_{1} = 100\\\sigma_1 = 1.5$

A procurement specialist has purchased 30 resistors from vendor 2 are assumed to be normally distributed with mean 105 ohms and standard deviation 2.0 ohms.

$x_{2,1}, x_{2,2}, ... , x_{2,30}\\\mu_{2} = 105\\\sigma_1 = 2.0$

The difference of two independent normally distributed random variables is normal, with its mean being equal to the difference of the two means, and its variance being the sum of the two variances.

Thus, the sampling distribution of $X_1-X_2$ is a normal distribution.

Mean =

$100 - 105 = -5$

Standard error =

$\sqrt{\displaystyle\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}}\\\\=\sqrt{\displaystyle\frac{(1.5)^2}{25} + \frac{(2)^2}{30}}\\\\= 0.473$

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3 years ago