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vekshin1
3 years ago
5

What is the length of the second base of a trapezoid if the length of one base is 24 and the length of the mid segment is 19

Mathematics
1 answer:
rodikova [14]3 years ago
6 0
The sum of the two bases is twice the length of the mid segment
24+x=19*2
x=14
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The directrix of a parabola is y=−4y=−4 . The focus of the parabola is (−2,−2)(−2,−2) .
Dennis_Churaev [7]
Because the focus is (-2,-2) and the directrix is y = -4, the vertex is (-2,-3).

Consider an arbitrary point (x,y) on the parabola.
The square of the distance between the focus and P is
(y+2)² + (x+2)²
The square of the distance from the point to the directrix is
(y+4)²

Therefore
(y+4)² = (y+2)² + (x+2)²
y² + 8y + 16 = y² + 4y + 4 + (x+2)²
4y = (x+2)² - 12
y = (1/4)(x+2)² - 3

Answer: y= \frac{1}{4} (x+2)^{2} - 3

5 0
3 years ago
The tangent, cotangent, and cosecant functions are odd , so the graphs of these functions have symmetry with respect to the:
Marina CMI [18]
<h2>Answer:</h2>

The tangent, cotangent, and cosecant functions are odd , so the graphs of these functions have symmetry with respect to the:

                                 Origin.

<h2>Step-by-step explanation:</h2>

A function f(x) is said to be a odd function if:

                    f(-x)=-f(x)

Also, an odd function always has a symmetry with respect to the origin.

whereas a function f(x) is said to be a even function if:

                      f(-x)=f(x)

Also, an even function has a symmetry with respect to the y-axis.

We know that:

Tangent function, cotangent function and cosecant function are odd functions.

Since,

\tan(-x)=-\tan x\\\\\cos (-x)=-\cot x\\\\\csc (-x)=-\csc x

( similarly sine function is also an odd function.

whereas cosine and secant function are even functions )

<em>Hence, the graph of tangent function, cotangent function and cosecant function  is symmetric about the origin.</em>

7 0
3 years ago
Malila wants to make the International Marine Signal flag shown. What is the area of the flag? _______________ inches squared
Kamila [148]

Answer:

The area of the flag is 1750 square inch

Step-by-step explanation:

The complete question is attached.

Solution

The flag consist of two triangles of base 12.5 inch and height 100 inch and one rectangle of width 5 inch and length of 100 inch

Total Area

(2 * 0.5 * 12.5 *100) + (5 *100)

1750 square inch

6 0
3 years ago
Given: △ABC, m∠C=90° m∠ABC=30°, AL ∠ bisector CL=6 ft. Find: LB
vlada-n [284]

For a better understanding of the solution given here please go through the diagram in the file attached.

To solve this question we will make use of the "Triangle Angle Bisector Theorem", which states that, "An angle bisector of an angle of a triangle divides the opposite side in two segments that are proportional to the other two sides of the triangle."

Thus, in our question, we will have:

\frac{LB}{CL}= \frac{AB}{AC}

The above equation can be rearranged as:

LB=CL\times \frac{AB}{AC}=\frac{CL}{(\frac{AC}{AB})}...(Equation 1)

If we have a proper look at the denominator which is \frac{AC}{AB}, we note that in \Delta ABC, \frac{AC}{AB}=Sin(\angle ABC)=Sin(30^\circ)

Thus, (Equation 1) wil give us:

LB=\frac{CL}{Sin(30^\circ)} =\frac{6}{0.5}=12

<u>Therefore, LB= 12 feet</u>

3 0
3 years ago
Help needed! - Geometry - 15 points - One question -
il63 [147K]

Answer: m<VUT= 70 degrees

Step-by-step explanation:

120= 50+ ?

?=70

6 0
3 years ago
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