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butalik [34]
3 years ago
7

There are 3 cats in a room and no other creatures.each cat has 2 ears, 4 paws, and 1 tail

Mathematics
1 answer:
maks197457 [2]3 years ago
7 0

Answer: theres really no question here

Step-by-step explanation:

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Planes A and B intersect.
myrzilka [38]

Answer:

Option (1)

Step-by-step explanation:

From the picture attached,

Two planes have been given as plane A and plane B.

Two lines 'm' and 'n' are on the plane A.

These lines intersect each other at a point W.

Therefore, point W describes the point of intersection of the lines 'm' and 'n'.

Option (1) will be the correct option.

8 0
3 years ago
A line segment is drawn from (+1, +9) to (+4, +9) on a coordinate grid. Which answer explains one way that the length of this li
Anettt [7]
The correct answer would be C
8 0
3 years ago
Read 2 more answers
The total cost of 5 boxes of pasta is $13. There are 12 ounces of pasta in each box. Each box of pasta cost the same amount. Wha
Bas_tet [7]

Answer: $10.40

Explanation:

First, find the cost of 1 box of pasta. 13/5 = 2.6, so $2.60 a box.

Next, find how many boxes there are. 48/12 = 4, so 4 boxes of pasta.

Finally, multiply 4*2.6 to get the final cost.

6 0
3 years ago
What is this question?? (needing help)
Free_Kalibri [48]

468 x 0.001 = 0.468

46.8 x 0.1 = 4.68

4.68 x 10^3 = 4680

0.468 x 10^2 = 46.8

Hope this helps!

5 0
3 years ago
Read 2 more answers
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
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