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aksik [14]
3 years ago
12

You go to see family in another city. So far you have gone 120 miles. The total trip is 360 miles. What fraction of the total tr

ip, in lowest terms, has been traveled?
Mathematics
2 answers:
beks73 [17]3 years ago
8 0
1/3 of the total trip has been traveled.
mylen [45]3 years ago
3 0
He is definitly right he beat me go ahead and give him brainliest .
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Can someone check my answers
Lelechka [254]
The first image with the answers are right but the second image is blank
8 0
3 years ago
Read 2 more answers
Identify the constant term in this expression. 25x + 9y + 20 + 2y
kvv77 [185]
20

Constant in a mathematical expression is a term whose value never changes.
The terms with x and y will vary based on the variable x and or y.
7 0
2 years ago
Is 4/7 greater or less than 3/5
baherus [9]
No, it is not.

4/7 ≈ 0.5714

3/5 = 0.6

Actually, 3/5 is greater than 4/7.

Another way you could do this is by multiplying 4/7 with 5/5 and by multiplying 3/5 with 7/7.

4/7 * 5/5 = 20/35

3/5 * 7/7 = 21/35

Have an awesome day! :)
6 0
3 years ago
your class is making a rectangular poster for a rally. the posters design is 6 in. high by 10 in. wide. the space allowed for th
Kay [80]

I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.

 PLEASE SEE ATTACHED IMAGE.

 For this case the area is given by:

 A = (22 + x) * (28 + x) = 722

 Rewriting we have:

 616 + 22x + 28x + x ^ 2 = 722

 x ^ 2 + 50x + 616 - 722 = 0

 x ^ 2 + 50x - 106 = 0

 Solving the polynomial we have:

 x1 = 2.04

 x2 = -52.04

 We take the positive root:

 x = 2.04 inches:

 Answer:

 The width of the border to the nearest inch is:

 x = 2inches

3 0
3 years ago
Read 2 more answers
The velocity of an automobile starting from rest is given by the equation below, where v is measured in feet per second and t is
podryga [215]

Answer:

(a) 0.408m/sec^2

(b) 0.134m/sec^2

(c) 0.039m/sec^2

Step-by-step explanation:

We have given velocity as function of t v(t)=\frac{85t}{(8t+14)}

Acceleration is equation rate if change of velocity with respect to time

So a=\frac{dv}{dt}=\frac{(8t+14)85-85t\times 8}{(8t+14)^2}

(a) Acceleration at t = 5 sec

a=\frac{(8\times 5+14)85-85\times 5\times 8}{(8\times 5+14)^2}=0.408m/sec^2

(b) Acceleration at t = 10 sec

a=\frac{(8\times 10+14)85-85\times 10\times 8}{(8\times 10+14)^2}=0.134m/sec^2

(c) Acceleration at t = 20 sec

a=\frac{(8\times 20+14)85-85\times 20\times 8}{(8\times 20+14)^2}=0.039m/sec^2

5 0
3 years ago
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