Answer:
$26 + X = $57
$26 + $31 = $57
X = $31
My first time ever answering a question hope it helped =) (And sry it took long)
Step-by-step explanation:
Answer:

Step-by-step explanation:
When we have a number to a fraction power, we need to note that
- It's the same as taking the denominator root of the base to the numerator power
Basically, for example,
is the same as
since the numerator is 1 (
) and the denominator is 2 (
).
Applying this same logic to
-


Hope this helped!
Answer:
Options A and B are true
(A) Before the authority increases tolls on any of the area bridges, it is required by law to hold public hearings at which objections to the proposed increase can be raised.
B. (B) Whenever bridge tolls are increased, the authority must pay a private contractor to adjust the automated toll-collecting machines.
Step-by-step explanation:
A. In a developed society, it's imperative for the authority to hold public hearings with stake holders to air their views before the tolls are increased, this would enable the authority to carry out proper assessment to know both the positive and negative impact of increasing the toll.
B. Increasing the tolls implies that there must be adjustment in the automated tolling machines and this would incur cost on the authority, this contract would be executed by private contractors.
Answer:
(a): <u>x</u><u> </u><u>is</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>ky</u><u> </u><u>is</u><u> </u><u>-</u><u>1</u>
<u>(</u><u>b</u><u>)</u><u>:</u><u> </u><u>k</u><u> </u><u>is</u><u> </u><u>-</u><u>2</u>
Step-by-step explanation:
Let: 3x + ky = 8 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em>
x - 2 ky = 5 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em>
<em> </em>Then multiply <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em><em> </em>by 2:
→ 6x + 2ky = 16, let it be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em>
Then <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em><em> </em><em>+</em><em> </em><em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em><em>:</em>
<em>
</em>
<em>T</em><em>h</em><em>e</em><em>n</em><em> </em><em>k</em><em>y</em><em> </em><em>:</em>

