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artcher [175]
3 years ago
7

Sorry to bother and all but i have no idea

Mathematics
1 answer:
wlad13 [49]3 years ago
3 0

Answer:

t=40

Step-by-step explanation:

first, add 21 to -21=0

to keep it balanced add 21 to 19=40

so t=40

hope this helps

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Given

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we have

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Squaring both sides, we have

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And finally

x=\dfrac{(d-c)^2}{a^2}-b

Note that, when we square both sides, we have to assume that

\dfrac{d-c}{a}>0

because we're assuming that this fraction equals a square root, which is positive.

So, if that fraction is positive you'll actually have roots: choose

a=1,\ b=0,\ c=2,\ d=6

and you'll have

\sqrt{x}+2=6 \iff \sqrt{x}=4 \iff x=16

Which is a valid solution. If, instead, the fraction is negative, you'll have extraneous roots: choose

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and you'll have

\sqrt{x}+10=4 \iff \sqrt{x}=-6

Squaring both sides (and here's the mistake!!) you'd have

x=36

which is not a solution for the equation, if we plug it in we have

\sqrt{x}+10=4 \implies \sqrt{36}+10=4 \implies 6+10=4

Which is clearly false

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