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3 years ago

Which expression represents the distance between -1 and 4

Mathematics

1 answer:

____ [38]3 years ago

5 0

Answer:

<h2><em>There is no expression to evaluate, please give us the expressions.</em></h2>

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Ineed help help me please

melamori03 [73]

The symbol ₁₂P₉ represents the permutations of 9 quantities out of 12.
By definition,
$_{12}P_{9} = \frac{12!}{(12-9)!} = \frac{12!}{3!}$

From the calculator,
12! = 479,001,600
3! = 6

Therefore
₁₂P₉ = 479001600/6 = 79,833,600

Answer: 79,833,600

8 0

3 years ago

Find the area of the rectangle

galben [10]

Rectangle is length multiplied by breadth

5 0

3 years ago

Read 2 more answers

he price of a pair of shoes increases from $68 to $77. What is the percent increase to the nearest percent?

tekilochka [14]

Answer:

an increase of 12%

Step-by-step explanation:

68 divided by 77 is 0.88 approximately

100-88 is 12

Tip:

do this for increase and decrease in percentage question

divide small number by big number, and subtract the quotient from 100

8 0

3 years ago

Read 2 more answers

Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

6 0

3 years ago

The length of a rectangle is 3 times the width. If the length is decreased by 4 meters and the width is increased by 1 meter, th

olga nikolaevna [1]

Good morning☕️

______

Answer:

w is the width

L is the length

p is the perimeter

w=9

L=27

___________________

Step-by-step explanation:

p=2[(L-4) + (w+1)]

⇔p=2[(3w-4) + (w+1)]

⇔p=2[4w-3]

⇔p=8w-6

⇔66=8w-6

⇔8w=72

⇔w=9

Then L=3w=27

6 0

3 years ago