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Svetllana [295]
3 years ago
7

If the two cars are now a straight-line distance of 17 kilometers apart, how far has the northbound car traveled?

Mathematics
1 answer:
Vladimir [108]3 years ago
6 0

Answer:

Step-by-step explanation:

The northbound car has traveled a distance of 6.2 miles.

Step-by-step explanation:

Step 1:

The eastbound car has traveled a distance of 5 miles and if a straight line is drawn between the two car's positions it would measure 8 miles.

This forms a triangle which has a hypotenuse measuring 8 miles while one of the other sides measures 5 miles.

Assume the distance traveled by the northbound car is x miles.

Step 2:

So the northbound car has traveled a distance of 6.244 miles. Rounding this off, we get 6.2 miles.

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Carla is selling chocolate bars for a fundraiser. Her goal is to sell 600 chocolate bars to win the top prize for selling them.
IceJOKER [234]

Answer:

She needs to sell for 64 more hours

Step-by-step explanation:

4 0
3 years ago
A data set includes 103 body temperatures of healthy adult humans having a mean of 98.1 F and a standard deviation of 0.56 F. Co
Ira Lisetskai [31]

Answer:

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

Step-by-step explanation:

The first step is finding the confidence interval

The sample size is 103.

The first step to solve this problem is finding how many degrees of freedom there are, that is, the sample size subtracted by 1. So

df = 103-1 = 102

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 102 and 0.005 in the t-distribution table, we have T = 2.63.

Now, we need to find the standard deviation of the sample. That is:

s = \frac{0.56}{\sqrt{103}} = 0.055

Now, we multiply T and s

M = T*s = 2.63*0.055 = 0.145

For the lower end of the interval, we subtract the mean by M. So 98.1 - 0.145 = 97.955F.

For the upper end of the interval, we add the mean to M. So 98.1 + 0.145 = 98.245F.

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

5 0
3 years ago
You owe $1456.32 on a credit card with a limit of $3500 what is your debt ratio?
Degger [83]
A because 40% of 3500 is 40%
5 0
3 years ago
Grandma usually puts 8 brownies into each of 4 containers, but now she has 8 containers. If she wants to divide the 32 brownies
tatiyna
She put 4 brownies in each container.
3 0
3 years ago
Read 2 more answers
What is the distance between the points (11,19) and (11,-6) in the coordinate plane?
IrinaK [193]

Answer: 25 units

Step-by-step explanation:

distance with negatives is still an addition but you have to turn the negative into a positive to get the answer.

6 0
1 year ago
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