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Given:
Vertices of a parallelogram ABCD are A(7,-4), B(-1,-4), C(-1,-12), D(7, -12).
To find:
Whether the parallelogram ABCD is a rhombus, rectangle or square.
Solution:
Distance formula:
Using distance formula, we get
Similarly,
All sides of parallelogram are equal.
Both diagonals are equal.
Since, all sides are equal and both diagonals are equal, therefore, the parallelogram ABCD is a square.
We know that, a square is special case of rectangles and rhombus.
So, parallelogram ABCD is a rhombus, rectangle or square. Therefore, the correct option is c.
From the given information, a exists jointly proportional to b and c.
then
Therefore, the value of a exists 2.
<h3>What is the value of a?</h3>Given, a exists jointly proportional to b and c.
Taking K as the constant of proportionality.
a = K b c
For b = 8 and c = 9, the value of a = 4
4 = K(8)(9)
4 = 72 K
Dividing the equation by 72, we get
Using the value of K in the equation:
Substitute the values of b = 2 and c = 18, in the above equation
a = 2
Therefore, the value of a exists 2.
To learn more the value of x refers to:
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