Answer:
m<C = 42°
Step-by-step explanation:
Given:
m<A = (2x - 2)°
m<C = (4x - 6)°
m<DBC = (5x + 4)°
Thus:
m<DBC = m<A + m<C (exterior angle theorem of a triangle)
(5x + 4)° = (2x - 2)° + (4x - 6)°
Solve for x
5x + 4 = 2x - 2 + 4x - 6
Collect like terms
5x + 4 = 6x - 8
5x - 6x = -4 - 8
-x = -12
Divide both sides by -1
x = 12
✔️m<C = (4x - 6)°
Plug in the value of x
m<C = 4(12) - 6 = 48 - 6
m<C = 42°
Answer:
Its d 5/10
Step-by-step explanation:
Answer:
E. 2, 3, 4
Step-by-step explanation:
The sum of the shortest two sides must exceed the longest side. That is only the case for the set ...
{2, 3, 4}
Answer:
Step-by-step explanation:
Convert this Quadratic Equation to Vertex Form by completing the square, ![\displaystyle y = a[x - h]^2 + k](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%20%3D%20a%5Bx%20-%20h%5D%5E2%20%2B%20k)
:
![\displaystyle -5x^2 -10x + 6 \\ \\ -5x^2 - 10x + 25 + k \\ -5[x^2 + 2x - 5] + k \\ -5[x^2 + 2x + 1] + k → -5[x^2 + 2x + 1] + 11 → f(x) = -5[x + 1]^2 + 11 \\ \\ Vertex: [-1, 11]; 11 = Maximum](https://tex.z-dn.net/?f=%5Cdisplaystyle%20-5x%5E2%20-10x%20%2B%206%20%5C%5C%20%5C%5C%20-5x%5E2%20-%2010x%20%2B%2025%20%2B%20k%20%5C%5C%20-5%5Bx%5E2%20%2B%202x%20-%205%5D%20%2B%20k%20%5C%5C%20-5%5Bx%5E2%20%2B%202x%20%2B%201%5D%20%2B%20k%20%E2%86%92%20-5%5Bx%5E2%20%2B%202x%20%2B%201%5D%20%2B%2011%20%E2%86%92%20f%28x%29%20%3D%20-5%5Bx%20%2B%201%5D%5E2%20%2B%2011%20%5C%5C%20%5C%5C%20Vertex%3A%20%5B-1%2C%2011%5D%3B%2011%20%3D%20Maximum)
So as you can see, each time we broke the equation down, we used the formula ![\displaystyle [\frac{b}{2}]^2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5B%5Cfrac%7Bb%7D%7B2%7D%5D%5E2)
to complete the square.
** In the Vertex Formula, −h gives the OPPOSITE terms of what they really are, so do not forget it.
I am joyous to assist you anytime.
Answer:
90
Step-by-step explanation:)
To obtain 
, sum the first 4 terms, using n = 1 to n = 4
= 6
+ 6
+ 6(2)² + 6(3)³
= (6 × 1) + (6 × 2) + (6 × 4) + (6 × 8)
= 6 + 12 + 24 + 48
= 90
