Let s = side length of square, then
200=s^2, or
s=sqrt(200)=sqrt(2*10^2)=10sqrt(2)
The diagonal turns out to be sqrt(s^2+s^2) by the Pythagoras theorem and equals sqrt(2s^2)=s*sqrt(2) = 10sqrt(2)*sqrt(2)=10*2=20.
In general, the diagonal D of a square with area A is given by
D=sqrt(2)*sqrt(A)=sqrt(2A)
In the case given it is Diagonal length = sqrt(2*200)=sqrt(400)=20 (as before)
The inverse is b. If 4x+1 .NE. 61, then x-5 .NE.10
Answer:
120x^3
Step-by-step explanation:
exponent rule --> a^b x a^c = a^b+^c
10^-6 x 10^7 = 10^6 + ^7
add / subtract numbers -- > -6 + 7 = 1
=2XX x 6X x 10
aponent rule --> a^b x a^c = a^b+^c
xxx = x^1 + ^1 + ^1
= 2 x 6x^1 + ^1 + ^1 x 10
= 2 x 6x^3 x 10
= 120x^3
Answer:
The new coordinates will be D(1,3) E(0,3) and F(-1,0)
Step-by-step explanation:
As can be seen in the picture, points A and B are moved one point negative in the y-axis, and three in the x-axis. Point C and D will have the same coordinates to form the new triangle.
7 / 8 = 0.875
It is a terminating decimal because the decimal has a finite amount of numbers.
