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WARRIOR [948]
3 years ago
5

How do you put 3y+x=12 in y=mx+b form

Mathematics
2 answers:
ira [324]3 years ago
7 0
Step 1: Rewrite the equation

3y+x=12

Step 2: To get y alone on the left side, subtract x on both sides

3y+x=12
-x -x
______
3y=-x+12

Step 3 (final step): To get y alone, divide each number by 3

3y = -x +12
/3 /3 /3
________
y=-1/3x+4


Final answer: y=-1/3x+4

Hope this helps :)
dezoksy [38]3 years ago
5 0
3y+x=12 in slope intercept form is y=-1/3+4
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Answer:

(x,-\frac{3}{2} x+2)

Step-by-step explanation:

For y= \frac{-3}{2} x+2  the set of points that include all solutions are (x,y) such that   y= \frac{-3}{2} x+2; then we have (x,y)=(x,\frac{-3}{2} x+2).

What is important to stress here is that (x,-\frac{3}{2} x+2) represents all of the solutions, while other points that we are given represent one solution  (for example, point (2,-1) is just one solution)

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Oksana_A [137]

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Step-by-step explanation:

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Oksanka [162]

Answer:

76

Step-by-step explanation:

given a quadratic equation in standard form : ax² + bx + c = 0 : a ≠ 0

then the discriminant is Δ = b² - 4ac

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b² - 4ac = (- 10)² - (4 × 3 × 2) = 100 - 24 = 76


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3 years ago
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