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4 years ago

12

30 POINTS!!!! EXPLAIN!

1 answer:

Reptile [31]4 years ago

7 0

Answer:

f(x+2)=3x+10

Explanation:

f(x+2) means replace all the xs with (x+2)

f(x)=3x+4

f(x+2)=3(x+2)+4

Now simplify

f(x+2)=3x+6+4

f(x+2)=3x+10

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What is the equation of this line?<br><br><br>y = 2x<br><br>y=12x<br><br>y=−2x<br><br>y=−12x

Anna [14]

Y=2X

Looking at the line you can see that it is moving up from left to right, making it positive. So -2X and -12X are incorrect.

Next we can find the slope by putting rise over run. Chose a point on the line, I’ll use (2,4).
On this point we rise to 4 and run over to 2.
So for rise over run we have 4/2 which is 2.
So y=2x is correct.

6 0

3 years ago

PLEASE SOLVE THIS FOR ME ITS DUE TOMORROW <br><br>Find an expression for the missing dimension.

denis-greek [22]

Answer:

The missing length is 2x+5

Step-by-step explanation:

Given equation of volume of cuboid is V= $2x^{3} +17x^{2} +46x+40$

Figure show that

Length of cuboid is ?

Width of cuboid is (x+4)

Height of cuboid is (x+2)

The volume of cuboid is given by

V=Length x Width x Height

Let Length be (bx+a)

The volume of cuboid will be

$V=(bx+a)(x+4)(x+2)$

$V=(bx+a)[x^{2}+4x+2x+8 ]$

$V=bx[x^{2}+6x+8]+a[x^{2}+6x+8]$

$V=[bx^{3}+6bx^{2}+8bx]+[ax^{2}+6ax+8a]$

$V=[bx^{3}+(6b+a)x^{2}+(8b+6a)x+8a]$

On comparing coefficient with given equation of volume

We get,

b=2 and 8a=40

Therefore, the value of a is 5 and b is 2

Thus, The missing length is bx+a=2x+5

7 0

4 years ago

Which of the following is true for the relation f(x)=2x^2+1

Aleksandr-060686 [28]

Where is “the following”

5 0

3 years ago

Problem 1: Use the Laplace Transforms to solve:

Leokris [45]

Transforming the ODE yields

$L\left\{y'' - y'\right\} = L\left\{e^{-3t}\right\}$

$(s^2 Y(s) - sy(0) - y'(0)) - (s Y(s) - y(0)) = \dfrac1{s+3}$

$(s^2 - s) Y(s) = \dfrac1{s+3}$

$Y(s) = \dfrac1{(s^2 - s)(s+3)} = \dfrac1{s(s-1)(s+3)}$

Partial fractions:

$Y(s) = \dfrac as + \dfrac b{s-1} + \dfrac c{s+3}$

$\implies 1 = a(s-1)(s+3) + b s(s+3) + c s(s - 1)$

$\implies 1 = -3 a + (2 a + 3 b - c) s + (a + b + c) s^2$

$\implies \begin{cases}-3a=1 \\ 2a+3b-c=0 \\ a+b+c=0\end{cases} \implies a=-\dfrac13, b=\dfrac14, c=\dfrac1{12}$

$\implies Y(s) = -\dfrac13 \times \dfrac1s + \dfrac14 \times \dfrac1{s-1} + \dfrac1{12} \times \dfrac1{s+3}$

Take the inverse transform:

$\boxed{y(t) = -\dfrac13 + \dfrac{e^t}4 + \dfrac{e^{-3t}}{12}}$

3 0

2 years ago

Jorge hiked 15.4 miles on Monday. He hiked 20.6 miles on Tuesday, and the rest of the 50-mile trail on Wednesday. If m represent

sergeinik [125]

Equation: 50-(20.6+15.4)
50-36
14 miles

8 0

3 years ago