we have that
x + 3y = 6 -------> first equation
2x − y = 10
x + 3y = 6-----> substract x both sides
-x+x+3y=6-x
3y=6-x-----> divide by 3 both sides
y=(6-x) /3
y=2-(x/3)
y=-(x/3)+2
therefore
the answer is
negative one thirdx + 2
Answer:
The solution to the system of linear equations is (1,9).
Step-by-step explanation:
The given system of linear equations
... (1)
.... (2)
Subtract equation (2) from equation (1) to eliminate y.
On combining like terms, we get
Add 8 on both sides.
Divide both sides by 8.
The value of x is 1.
Substitute x=1 in equation (1).
The value of y is 9.
Therefore the solution to the system of linear equations is (1,9).
Using Gauss's method
Total number of terms = [15-(-129)]/4+1=36+1=37
Add
S=15+11+7+....-125-129
S=-129-125-...+7+11+15
--------------------------------
2S=-114-114-114...(37 times)
=>
sum=S=(1/2)*(-114)*37=-2109
Using AP, T(n)=15+11+7+....-129
T(n)=19-4n => T(1)=15, T(37)=-129
S(n)=(1/2)(37)(T(1)+T(37)=(1/2)37(15-129)=2109
To find the y-coordinate of the vertex, simply plug the value of -b / 2a into the equation for x and solve for y.
Yes it is
it’s the 41st term
EXPLANATION:
the nth term would be 15n+35
because the terms go up by 15 and you add 35 to get to the term.
1. 2. 3. 4.
50. 65. 80. 95
1000- 35= 965
965/15=41
