Answer:
787.4016 inches
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
Answer:
Incorrect
Step-by-step explanation:
The correct answer is A.
The slope-intercept form is y-y₁=m(x-x₁)
The problem with B is that if you take out the coordinates for x₁ and y₁, you get the coordinates (1,4). This coordinate does not land on the line.
The coordinates for A is (-1,4). This point does land on the line.
Answer:
i. 1.63 s
ii. The negative time cannot be used in this context
Step-by-step explanation:
i. Since h = −640t² and the rocket descends 1,690 m, h = -1,690 m (since there is a drop in height).
So, h = -640t²
t² = h/-640
t = √(- h/640)
Substituting h into the equation, we have
t = √(- h/640)
t = √[-(-1,690)/640]
t = √2.640625
t = 1.625
t ≈ 1.63 s
ii. So, the negative time cannot be used in this context because, the height drop is negative.
For a geometric sequence
<em>a</em>, <em>ar</em>, <em>ar</em> ², <em>ar</em> ³, …
the <em>n</em>-th term in the sequence is <em>ar</em> <em>ⁿ</em> ⁻ ¹.
The first sequence is
1, 3, 9, 27, …
so it's clear that <em>a</em> = 1 and <em>r</em> = 3, and so the <em>n</em>-th term is 3<em>ⁿ</em> ⁻ ¹.
The second sequence is
400, 200, 100, 50, …
so of course <em>a</em> = 400, and you can easily solve for <em>r</em> :
200 = 400<em>r</em> ==> <em>r</em> = 200/400 = 1/2
Then the <em>n</em>-th term is 400 (1/2)<em>ⁿ</em> ⁻ ¹.
Similarly, the other sequences are given by
3rd: … 4 × 2<em>ⁿ</em> ⁻ ¹
4th: … 400 (1/4)<em>ⁿ</em> ⁻ ¹
5th: … 5<em>ⁿ</em> ⁻ ¹
6th: … 1000 (1/2)<em>ⁿ</em> ⁻ ¹
7th: … 2 × 5<em>ⁿ</em> ⁻ ¹
