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aalyn [17]
3 years ago
11

Complete the equation for f(x)

Mathematics
1 answer:
I am Lyosha [343]3 years ago
8 0

Answer:

f(x)=9

Step-by-step explanation:

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For each of the following vector fields F , decide whether it is conservative or not by computing the appropriate first order pa
Mazyrski [523]

Answer:

(a)

Conservative

(b)

Not conservative

(c)

Conservative.

Step-by-step explanation:

(a)

\mathbf{F}(x,y) = (-10x+7y,7x+6y)

Notice that

\frac{\partial\mathbf{F}_y}{\partial x} = 7

and

\frac{\partial\mathbf{F}_x}{\partial y} = 7

Therefore the field is conservative.

(b)

Notice that

\mathbf{F}(x,y) = (-5y,-4x)

and

\frac{\partial\mathbf{F}_y}{\partial x} = -4

but

\frac{\partial\mathbf{F}_x}{\partial y} = -5

Therefore is not conservative.

(c)

Notice that

To prove that the vector field is conservative you have to compute the curl of the vector field and you would get that.

\mathbf{F}(x,y,z) = (-5x,-4y,1)

\nabla \times \mathbf{F} =  (0,0,0)

Therefore your vector field is conservative.

6 0
4 years ago
Which are equivalent (same value)? *<br> 31%<br> 31 per 100<br> 31/100<br> all of the above
Vinil7 [7]

Answer:

All of the above.

Step-by-step explanation:

31%=.31=31/100.

even if there is 31 per 100, it is the same. what if there is twice the value. 62/200. This is still reduced to the same number 31/100. There is still 31% of that thing.

5 0
3 years ago
Read 2 more answers
What Are Zeros of F(x)=3(×_5​
Misha Larkins [42]

Answer:

The Zeros:

f(x)= 3(x –5)

X= 5

8 0
3 years ago
Verify that:
Lelu [443]

Answer:

See Below.

Step-by-step explanation:

Problem 1)

We want to verify that:

\displaystyle \left(\cos(x)\right)\left(\cot(x)\right)=\csc(x)-\sin(x)

Note that cot(x) = cos(x) / sin(x). Hence:

\displaystyle \left(\cos(x)\right)\left(\frac{\cos(x)}{\sin(x)}\right)=\csc(x)-\sin(x)

Multiply:

\displaystyle \frac{\cos^2(x)}{\sin(x)}=\csc(x)-\sin(x)

Recall that Pythagorean Identity: sin²(x) + cos²(x) = 1 or cos²(x) = 1 - sin²(x). Substitute:

\displaystyle \frac{1-\sin^2(x)}{\sin(x)}=\csc(x)-\sin(x)

Split:

\displaystyle \frac{1}{\sin(x)}-\frac{\sin^2(x)}{\sin(x)}=\csc(x)-\sin(x)

Simplify:

\csc(x)-\sin(x)=\csc(x)-\sin(x)

Problem 2)

We want to verify that:

\displaystyle (\csc(x)-\cot(x))^2=\frac{1-\cos(x)}{1+\cos(x)}

Square:

\displaystyle \csc^2(x)-2\csc(x)\cot(x)+\cot^2(x)=\frac{1-\cos(x)}{1+\cos(x)}

Convert csc(x) to 1 / sin(x) and cot(x) to cos(x) / sin(x). Thus:

\displaystyle \frac{1}{\sin^2(x)}-\frac{2\cos(x)}{\sin^2(x)}+\frac{\cos^2(x)}{\sin^2(x)}=\frac{1-\cos(x)}{1+\cos(x)}

Factor out the sin²(x) from the denominator:

\displaystyle \frac{1}{\sin^2(x)}\left(1-2\cos(x)+\cos^2(x)\right)=\frac{1-\cos(x)}{1+\cos(x)}

Factor (perfect square trinomial):

\displaystyle \frac{1}{\sin^2(x)}\left((\cos(x)-1)^2\right)=\frac{1-\cos(x)}{1+\cos(x)}

Using the Pythagorean Identity, we know that sin²(x) = 1 - cos²(x). Hence:

\displaystyle \frac{(\cos(x)-1)^2}{1-\cos^2(x)}=\frac{1-\cos(x)}{1+\cos(x)}

Factor (difference of two squares):

\displaystyle \frac{(\cos(x)-1)^2}{(1-\cos(x))(1+\cos(x))}=\frac{1-\cos(x)}{1+\cos(x)}

Factor out a negative from the first factor in the denominator:

\displaystyle \frac{(\cos(x)-1)^2}{-(\cos(x)-1)(1+\cos(x))}=\frac{1-\cos(x)}{1+\cos(x)}

Cancel:

\displaystyle \frac{\cos(x)-1}{-(1+\cos(x))}=\frac{1-\cos(x)}{1+\cos(x)}

Distribute the negative into the numerator. Therefore:

\displaystyle \frac{1-\cos(x)}{1+\cos(x)}=\displaystyle \frac{1-\cos(x)}{1+\cos(x)}

3 0
3 years ago
I Just Wanna Be Nice And Gice Out A Free Brainliest :D
dolphi86 [110]

Answer:

THANK YOUUUU

Step-by-step explanation:

3 0
4 years ago
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