Please Help me w/ 6th-grade math I'll give brainliest :)

Mathematics

1 answer:

Setler79 [48]3 years ago

7 0

Answer:

TThe 3rd 4th and 5th option hope this helps im not sure

Step-by-step explanation:

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5.65 x 10 to the 5th power + 4.87 * 10 to the 3rd power

Sunny_sXe [5.5K]

Answer:

569870

Hope this helps you. Do mark me as brainly

5 0

3 years ago

Read 2 more answers

Give an example how to convert <br> $8.50 multiplied by 8 equal 68

tatuchka [14]

If you're looking for a word problem here's one,

Nichole has $8.50 and she decides to invest it in to a company worth $1,000,000 in a year the company is worth $8,000,000 as the company went up in value so did Nichole's investment, how much was Nichole's Investment worth at the end of that year?

If your'e looking for someone to show the math here's that,

if you take the decimal first and multiply that by 8 you get 4 because 0.5*8=4, then you multiply the whole number and get 64 because 8*8=64, add the two together and you get 68, 64+4=68

6 0

4 years ago

Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?

Marina86 [1]

Answer:

x=1+i√19,1-i√19

Step-by-step explanation:

Write the problem as a mathematical expression.

Subtract from both sides of the equation.

Use the quadratic formula to find the solutions.

Substitute the values, and into the quadratic formula and Simplify.

Simplify the numerator. Multiply by Simplify

4 0

3 years ago

Draw a quadrilateral ABCD with AB = 8.5cm, BC =4.5cm, CD =5cm , DA = 6cm , BD =7.5cm. Draw an equal area Triangle

irina1246 [14]

Answer:

Check below please

Step-by-step explanation:

A quadrilateral is a polygon with four sides.

Then let's plot it, check it below.

1) Since 5 line segments were given for a quadrilateral, one of them is an interior one. In this quadrilateral, a rhombus. We have a diagonal, id est a line segment between non-consecutive points.

2) Let's calculate the area of this rhombus. Since this polygon is made up of two triangles let's find it using Heron's Formula, not very popular. But equally valid, also we don't have the height nor angles.

All we need is the semi-perimeter, (half of the Perimeter (2P) and plug it in the formula:

$\bigtriangleup ABD semi-perimeter:\frac{6+8.5+7.5}{2} \therefore s=11\\Area \:\bigtriangleup ABD=\sqrt{11(11-6)(11-8.5)(11-7.5)}=\frac{5\sqrt{77}}{2} \approx21.94 cm\\\\\bigtriangleup \:BCD\: semi-perimeter:\frac{4.5+5+7.5}{2} \therefore s=8.5\\\\Area \bigtriangleup BCD=\sqrt{8.5(8.5-4.5)(8.5-5)(8.5-7.5)}=\sqrt{119}\approx 10.90$