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larisa86 [58]
2 years ago
6

Please Help me w/ 6th-grade math I'll give brainliest :)

Mathematics
1 answer:
Setler79 [48]2 years ago
7 0

Answer:

TThe 3rd 4th and 5th option hope this helps im not sure

Step-by-step explanation:

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A flowerpot has a circular base with a diameter of 27 centimeters. Find the circumference of the base of the flowerpot. Round to
ValentinkaMS [17]

Answer:

84.82cm :}

Step-by-step explanation:

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3 years ago
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8 0
2 years ago
In the oak forest, 60 kids are playing capture the flag.That is 40 percent of all kids in the park.How many kids are in the park
Romashka [77]

Answer:

150 kids

Step-by-step explanation:

If 60 kids is 40% of the total kids, we can add another 60 to get 80% and then half of 60 (30) to bring the total up to 100% of the kids.

6 0
2 years ago
Read 2 more answers
A student ran out of time on a multiple choice exam and randomly guessed the answers for two problems. Each problem had 5 answer
choli [55]

Answer:

there is a 64% chance that the student got both problems wrong

a 32% chance that they got only 1 correct

and a 4% chance that they got both correct

Step-by-step explanation:

There are 25 total possible combinations of answers, with 8 possible combinations where the student would get 1 answer right, and 1 combination where the student would get both answers correct.

25-9=16

\frac{16}{25} =\frac{x}{100}

\frac{64}{100}

64%

\frac{8}{25} =\frac{y}{100}

\frac{32}{100}

32%

\frac{1}{25} =\frac{z}{100}

\frac{4}{100}

4%

3 0
3 years ago
An optical inspection system is used to distinguish among different part types. The probability of a correct classification of a
Whitepunk [10]

Answer: \mu=2.88\ \&\ \sigma^2=0.115

Step-by-step explanation:

Given : The probability of a correct classification of any part is : p=0.96

sample size : n= 3

The formula to find the mean and variance for binomial distribution is given by :-

\mu=np\\\\\sigma^2=np(1-p)

Let the random variable X denote the number of parts that are correctly classified.

The, for the given situation, we have

\mu=3(0.96)=2.88\\\\\sigma^2=(3)(0.96)(1-0.96)=0.1152\approx0.115

Hence, the mean and variance of X are 2.88 and 0.115 respectively.

4 0
3 years ago
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