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lozanna [386]
3 years ago
5

Find a + b, 2a + 3b, |a|, and |a − b|. a = i + 4j − 2k, b = −4i − j + 6k

Mathematics
1 answer:
emmasim [6.3K]3 years ago
7 0
A + b = i + 4j - 2k + (-4i - j + 6k)

= i + 4j - 2k - 4i - j + 6k

= -3i + 3j + 4k
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qaws [65]

question 4 is A

question 5 is 43.6

question 5 showing work

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then I would divide it by 3 for each day

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131÷3=43.6

7 0
2 years ago
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State the domain and range<br> of f(x) = x²
ANTONII [103]

Answer:

Domain : All real numbers

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Step-by-step explanation:

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7 0
2 years ago
Determine whether the ordered pair (1, 1) is a solution of the inequality. y ≤ -3x+1
solong [7]

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Answer:  \textsf{(1, 1) is NOT a solution of the inequality}

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Given:  y \le-3x + 1

Find:  \textsf{Determine if (1, 1) is a solution of the inequality}

Solution:  In order to determine if (1, 1) is a solution we need to plug in 1 for the x values and 1 for the y values and see if the equation evaluated to true.

<u>Plug in the values</u>

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As we can see the expression states that 1 is less than or equal to -2 which is false therefore (1, 1) is NOT a solution of the inequality.

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1 year ago
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enot [183]

Answer:

2x - 12 + 6 = 4x - 4

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-2 = 2x

x= -2/2

x = -1

5 0
2 years ago
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