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lozanna [386]
3 years ago
5

Find a + b, 2a + 3b, |a|, and |a − b|. a = i + 4j − 2k, b = −4i − j + 6k

Mathematics
1 answer:
emmasim [6.3K]3 years ago
7 0
A + b = i + 4j - 2k + (-4i - j + 6k)

= i + 4j - 2k - 4i - j + 6k

= -3i + 3j + 4k
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What is the sum of 7 2/6 + 2 1/4
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115/12

Step-by-step explanation:

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Chris is splitting 6 quarts of ice cream with 9 members of the team. If the ice cream is split evenly. How many cups will each p
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Each person gets 2 2/3 cups of ice-cream
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Suppose a bag contains many marbles, 54% of which are purple. You draw 5 marbles from the bag with replacement.
dolphi86 [110]

Part A

Use the binomial probability distribution formula.

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n = 5 = sample size

x = 2 = number of purple we want to get

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The \frac{n!}{x!(n-x)!} portion is from the nCr combination formula. The exclamation marks indicate a factorial.

Alternatively, you could use Pascal's Triangle for that portion.

<h3>Answer: 0.283831776</h3>

This decimal value is exact. Round it however you need to.

============================================================

Part B

To find the expected value, aka the mean, we multiply the sample size and probability of getting a purple marble on any single selection.

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The probability that they all select front drivers side,tire is: \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}=\frac{1}{256}

Similarly,

The probability that they all select front passenger side, tire is: \frac{1}{256}

The probability that they all select rear driver side,tire is: \frac{1}{256}

The probability that they all select rear passenger side, tire is: \frac{1}{256}

Hence, the probability that all four workers select the same​ tire = \frac{1}{256}+ \frac{1}{256}+\frac{1}{256}+\frac{1}{256}

the probability that all four workers select the same​ tire = \frac{4}{256}=\frac{1}{64}=0.015625

Hence, the required probability is 0.015625.

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3 years ago
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11400 ÷12 = 950 hundreds

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