Someone help meh plzz

Which is the box-and-whisker plot for the data set?

ivann1987 [24]

It is the first graph. The median of the number list is 14. The Q1 is 9 ((7+11)/2) and the Q3 is 17 ((19+15)/2) the two outliers are 6 and 21

8 0

3 years ago

What is the value of n?

sineoko [7]

A. 69 degrees

exterior angles should equal 360 degrees so just add 131+160= 291 , 360-291= 69 degrees

or u can find it by finding the interior angle degrees by using supplementary angles. 180-131= 49 , 180-160= 20, 20+49=69, 180-69= 111 so the missing exterior angle corresponding interior is 111 and u can use supplementary angles to find the exterior. 180-111= 69 degrees

5 0

2 years ago

Which statements are true? Check all that apply. Based on both tables, there is no association between gender and enjoying danci

Maru [420]

Answer:

b c e

Step-by-step explanation:

6 0

3 years ago

In the Reflecting Ball Game a ball can be launched from points 1, 2, 3, 4, 5 or 6 in the direction shown. When a ball hits a sid

natulia [17]

Answer:

$24\sqrt{2}$

Step-by-step explanation:

We can measure the number of diagonals each path takes:

From point 1, the path travels 6 diagonals, ending up at point D.

From point 2, the path travels 12 diagonals, ending back at point A.*

From point 3, the path travels 3 diagonals, ending at point B.

From point 4, the path travels 9 diagonals, ending at point C.

From point 6, the path travels 10 diagonals, ending at point D.

Since your question mentions each are 2 cm by 2 cm, this is equivalent to $2\sqrt{2}$ .

We can easily conclude that the maximum is 12 diagonals. Thus, Solving our equation gives: 12 * $2\sqrt{2}$ = $24\sqrt{2}$ as our final answer.

*Note: This path will pass through point five, that is, following the diagram you described. If this is true, then there is no need to solve the longest possible path for point 5.

5 0

2 years ago

In recent years, only 79% of the fruit sold at Fred's Fruit stand has been any good. Fred recently started buying fruit from new

Juli2301 [7.4K]

Answer:

The p-value of the test is 0.0485 < 0.05, also less than 0.07, so there is sufficient evidence to conclude that there is a statistically significant increase in the percentage of good fruit, for both significance levels, thus the change in significance levels do not change the conclusion.

Step-by-step explanation:

79% of the fruit sold at Fred's Fruit stand has been any good. Test if there has been an increase.

At the null hypothesis, we test if there has been no increase, that is, the proportion is still of 79%, so:

$H_0: p = 0.79$

At the alternative hypothesis, we test if there has been an increase, that is, more than 79% being good, so:

$H_1: p > 0.79$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.79 is tested at the null hypothesis:

This means that $\mu = 0.79, \sigma = \sqrt{0.79*0.21}$

In a random sample if 475 pieces, 85 were bad.

So 475 - 85 = 390 were good, and:

$n = 475, X = \frac{390}{475} = 0.8211$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.8211 - 0.79}{\frac{\sqrt{0.79*0.21}}{\sqrt{475}}}$

$z = 1.66$

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion above 0.8211, which is 1 subtracted by the p-value of Z = 1.66.

Looking at the z-table, z = 1.66 has a p-value of 0.9515.

1 - 0.9515 = 0.0485

The p-value of the test is 0.0485 < 0.05, also less than 0.07, so there is sufficient evidence to conclude that there is a statistically significant increase in the percentage of good fruit, for both significance levels, thus the change in significance levels do not change the conclusion.

5 0

3 years ago